The difference 25(d−10)−23(d+6)25(d−10)−23(d+6) is
2 answers:
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Given:
The given sets are:
Set a : 200, 104, 100, 160.
Set b: 270, 400, 483, 300, x.
Mean of set a: mean of set b= 3:8
To find:
The value of x.
Solution:
Formula for mean:
The mean of set of a is:
The mean of set of b is:
It is given that,
Mean of set a: mean of set b= 3:8
Isolate the variable x.
Divide both sides by 3.
Therefore, the value of x is 427.