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OverLord2011 [107]
2 years ago
6

How many 1/3 cubes does it take to fill a box with a width of 2 2/3 inches length 3 1/3 inches and height 2 1/3

Mathematics
1 answer:
Paladinen [302]2 years ago
7 0

Answer:

560

Step-by-step explanation:

I assume 1/3 is the side length of the cubes.

There's two ways to solve this:

1. Find the volume of the box, then divide by the volume of the cubes.

Or 2. Find the number of cubes per each side length, the find the volume in terms of cubes.

Either way, we need to convert the mixed fractions to improper fractions.

W = 2⅔ = (2×3+2)/3 = 8/3 inches

L = 3⅓ = (3×3+1)/3 = 10/3 inches

H = 2⅓ = (2×3+1)/3 = 7/3 inches

Using the first method, the volume of the box is:

V = (8/3 in) (10/3 in) (7/3 in) = 560/27 in³

The volume of a cube is:

V = (1/3 in)³ = 1/27 in³

So the number of cubes in the box is:

(560/27 in³) / (1/27 in³) = 560

Using the second method, the cubes per each side of the box is:

W = (8/3 in) / (1/3 in) = 8

L = (10/3 in) / (1/3 in) = 10

H = (7/3 in) / (1/3 in) = 7

So the number of cubes is:

8 × 10 × 7 = 560

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2 years ago
Simplify 3a + 4b + 5c + (-2a) + b
ad-work [718]

Answer:

<em> </em><em>a </em><em>+</em><em> </em><em>5</em><em>b</em><em> </em><em>+</em><em> </em><em>5</em><em>c</em>

Step-by-step explanation:

here's your solution

=> 3a + 4b + 5c +(-2a) + b

=> solve for like term

=> 3a - 2a + 4b + b + 5c

=> a + 5b + 5c

hope it helps

7 0
3 years ago
Read 2 more answers
How many decimal places do you move to change meters to centimeters?
vlada-n [284]
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8 0
3 years ago
Below, the two-way table is given for a class
Nataliya [291]

Answer:

2/7 = 29% (nearest percent)

Step-by-step explanation:

Calculate the totals and add them to the table:

\begin{array}{| c | c | c | c | c | c |}\cline{1-6} & \sf Freshman & \sf Sophmore & \sf Juniors & \sf Seniors & \sf Total \\\cline{1-6} \sf Male & 4 & 6 & 2 & 2 & 14\\\cline{1-6} \sf Female & 3 & 4 & 6 & 3 & 16\\\cline{1-6} \sf Total & 7 & 10 & 8 & 5 & 30\\\cline{1-6}\end{array}

<u>Probability Formula</u>

\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}

Let P(A) = probability that the student is a freshman

Let P(B) = probability that the student is male

Use the given table to calculate the probability that the <u>student is male</u>:

\sf \implies P(B)=\dfrac{14}{30}

And the probability that the <u>student is a freshman </u><u>and </u><u>male:</u>

\implies \sf P(A \cap B)=\dfrac{4}{30}

To find the probability that the student owns a credit card given that the they are a freshman, use the conditional probability formula:

<u>Conditional Probability Formula</u>

The probability of A given B is:

\sf P(A|B)=\dfrac{P(A \cap B)}{P(B)}

Substitute the found values into the formula:

\implies \sf P(Freshman|Male)=\dfrac{\dfrac{4}{30}}{\dfrac{14}{30}}=\dfrac{4}{14}=\dfrac{2}{7}=0.28571...=29\%

Therefore, the probability that the student is a freshman given they are male is 29% (nearest percent).

Learn more about conditional probability here:

brainly.com/question/28028208

brainly.com/question/23957743

8 0
1 year ago
Find a value for x if 1/x &gt; x
Ymorist [56]

Since x can't be zero (it sits at the denominator of the left hand side), let's split cases:

If x is positive

It this case, we can multiply both sides by x without changing the inequality sign:

\dfrac{1}{x} > x \iff 1 > x^2 \iff x \in (-1,1)

But since we're assuming that x is positive, we can only accept the numbers between 0 and 1.

If x is negative

It this case, in order to multiply both sides by x we have to change the inequality sign:

\dfrac{1}{x} > x \iff 1 < x^2 \iff x \in (-\infty,-1) \cup (1,\infty)

But since we're assuming that x is negative, we can only accept the numbers which are smaller than -1.

So, putting all the pieces together, we have that the solution is given by the following interval:

(-\infty, -1) \cup (0,1)

6 0
3 years ago
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