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Firlakuza [10]
3 years ago
7

How much less than 0.1 is 0.001

Mathematics
1 answer:
dem82 [27]3 years ago
4 0
Well, it's SMALLER by 100, because 0.001 times 100 = 0.1 ;-)
I hope I helped! =D
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Write -1.64 as a fraction in simplest form
Mashutka [201]

To write the following as a fraction, we will;

First write the decimal over 1

That is;

\frac{-1.64}{1}

Then multiply the numerator and the denominator by 100

\frac{-1.64\text{ }\times100}{1\text{ }\times100}\frac{-164}{100}

Now, go ahead and reduce the fraction

=-\frac{41}{25}=\text{ -1}\frac{16}{25}

3 0
1 year ago
Can someone help me with this word problem? I will mark anyone that offers me a useful answer the most brainiest!
OLEGan [10]

Step-by-step explanation:

Hours of work- Alvin: 6 hours Theodore: 4.5 hours Simon: 1.25 hours

  1. 6+1.25+4.5= 11.75 hours Calculate the total amount of hours all of them worked together
  2. 61÷11.75= $5.19 Divide the total amount of money by number of hours.
  3. 5.19×6= $31.14 for Alvin, 5.19×4.5= $25.43 for Theodore, 5.19×1.25= $6.49 for Simon Multiply the number of hours worked by each chipmunk by the money made per hour.
6 0
3 years ago
#5 plz plz plz help me it is due tomorrow
Burka [1]
Do 560 * .38 which is 212.8 or B, it could be C if you are rounding but 212.8 is the exact answer
5 0
3 years ago
Read 2 more answers
PLEASE ANSWER WILL GIVE POINTS!!!!!!!!!!!
iris [78.8K]

Given:

The figure of a right triangle ABC.

To find:

The trigonometric ratios \sin B, \tan A, \cos B.

Solution:

Using Pythagoras theorem,

Hypotenuse^2=Perpendicular^2+Base^2

AB^2=AC^2+BC^2

(10)^2=(6)^2+BC^2

100-36=BC^2

64=BC^2

Taking square root on both sides.

\sqrt{64}=BC

8=BC

So, measure of BC is 8 units.

Now,

\sin \theta=\dfrac{Opposite}{Hypotenuse}

\sin B=\dfrac{AC}{AB}

\sin B=\dfrac{6}{10}

\sin B=\dfrac{3}{5}

Similarly,

\tan \theta=\dfrac{Opposite}{Adjacent}

\tan A=\dfrac{AC}{BC}

\tan A=\dfrac{6}{8}

\tan A=\dfrac{3}{4}

And,

\cos \theta=\dfrac{Adjacent}{Hypotenuse}

\cos B=\dfrac{BC}{AB}

\cos B=\dfrac{8}{10}

\cos B=\dfrac{4}{5}

Therefore, the required trigonometric ration are \sin B=\dfrac{3}{5}, \tan A=\dfrac{3}{4}, \cos B=\dfrac{4}{5}.

6 0
3 years ago
The sum<br>as three consicutive<br>multplies of 11 is<br>363<br>there eltiples.​
Dmitry [639]

Answer:

Three consecutive multiples are 110,121 and 132 which has the sum of 363. 33C = 363; C = 33, By substituting C = 33 in numbers 11C, 11(C – 1) and 11(C + 1) we get values 110, 121, 132.

3 0
3 years ago
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