We can find the midpoint of any line segment using the midpoint formula: M=(x1+x2/2,y1+y2/2). Essentially, the midpoint formula finds the average of two points. If we use B and the first point and C as the second, when we plug in our values we would have M=(5-4/2,9-5/2). This can be simplified to M=(1/2,4/2) or M=(1/2,2) which is the final answer.
<span>I hope this helps.</span>
Answer:
Step-by-step explanation:
If you can present a problem in Latex, you can do anything. I don't know what the question mark is for. I'm just ignoring it.
55 2/3 * 66 5/6
One of the ways to get the answer is to use decimals
55.666666667 * 66.833333333 = 3720.38889
Another way to do this problem is to break up one of the numbers
55 2/3 (66 + 5/6) You can do this if you know how to use the distributive property.
55 2/3 * 66 + 55 2/3 * 5/6
( (165 + 2) / 3) * 66 + (165 + 2)/3 * 5/6
167/3 * 66 + 167 / 3 * 5/6
167 * 22 + (167 * 5 / (3 * 6)
3674 + 835 / 18
3674 + 46 7/18
3720 7/18
If none of these seem right and you have choices, please list them.
I cant hardly see it ,what's the question?
Answer:
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Step-by-step explanation:

Answer:
D is the answer
64,000 exponential function
Step-by-step explanation:
64,000 exponential function
The number of bacteria in a colony doubles every 210 minutes.
The population of bacteria = 8000
Determine how many times the population will double.
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= 3
Multiply the population by 2 a total of 3 times.
8000 × 2³ = 64,000