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3 years ago

Look at pic for answer will mark brainilest PLEASE

Mathematics

1 answer:

SCORPION-xisa [38]3 years ago

5 0

Answer:

I believe B is the independent variable.

Step-by-step explanation:

an independent variable represents a quantity that can be manipulated in this situation it would the number of bushels that can be manipulated.

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Tina is making a scale model of A monument that is 155 feet tall she uses a scale of 1 inch = 5 feet how tall should Tina make h

fenix001 [56]

Tina should make 31 inch tall model to replicate 155 feet tall monument.

Step-by-step explanation:

This problem can be solved by direct unitary methods easily-

Firstly, Scale is the ratio of the dimension of the original substance to the dimension of a model

Scale= original dimension/ model dimension

Model is the miniaturised representation of a substance.

The monument is 155 feet tall

Tina replicates it with a scale 1inch: 5 feet

Thus, this means that Tina would need 155*1/5 = 31 inch tall model to replicate the complete length of the monument.

Hence Tina needs to make 31-inch tall model.

3 0

3 years ago

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Plzzz help .........

velikii [3]

C. sounds like the most reasonable answer to the question.<span />

3 0

3 years ago

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How many times is 10 as much as 46

Alexxandr [17]

4.6

10/46

10(x)=46
x=4.6

7 0

3 years ago

What is the value of 8C5? A. 40 B. 56 C. 960 D. 6720

Rina8888 [55]

The correct answer will be A 40

7 0

4 years ago

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A sheet of paper 90 cm-by-66 cm is made into an open box (i.e. there's no top), by cutting x-cm squares out of each corner and f

NNADVOKAT [17]

Answer:

$26 - \sqrt{181}$ cm

Step-by-step explanation:

The volume of the box is:

V = height * length * width

V = x*(66 - 2*x)*(90 - 2*x)

V = (66*x - 2*x^2)*(90 - 2*x)

V = 5940*x - 132*x^2 - 180*x^2 + 4*x^3

V = 4*x^3 - 312*x^2 + 5940*x

where x is the length of the sides of the squares, in cm.

The mathematical problem is :

Maximize: V = 4*x^3 - 312*x^2 + 5940*x

subject to:

x > 0

2*x < 66 <=> x < 33

In the maximum, the first derivative of V, dV/dx, is equal to zero

dV/dx = 12*x^2 - 624*x + 5940

From quadratic formula

$x = \frac{-b \pm \sqrt{b^2 - 4(a)(c)}}{2(a)}$

$x = \frac{624 \pm \sqrt{(-624)^2 - 4(12)(5940)}}{2(12)}$

$x = \frac{624 \pm \sqrt{104256}}{24}$

$x = \frac{624 \pm \sqrt{2^6*3^2*181}}{24}$

$x = \frac{624 \pm 8*3*\sqrt{181}}{24}$

$x_1 = \frac{624 + 24*\sqrt{181}}{24}$

$x_1 = 26 + \sqrt{181}$

$x_2 = \frac{624 - 24*\sqrt{181}}{24}$

$x_2 = 26 - \sqrt{181}$

But $x_1 > 33$ , then is not the correct answer.

5 0

3 years ago