2 years ago

Y^-1 dy +ye^(cosx) sinxdx=0

Mathematics

1 answer:

olga nikolaevna [1]2 years ago

3 0

Please see the answer here

http://www.wolframalpha.com/input/?i=y%5E-1%20dy%20%2Bye%5E%28cosx%29%20sinxdx%3D0

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Aloiza [94]

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If one-sixth of a number plus one-third returns two-thirds of that number What is the number

Solnce55 [7]

Answer:

$x= \frac{2}{3}$

Step-by-step explanation:

Let the number be x

Given

$\frac{1}{6}x + \frac{1}{3} = \frac{2}{3}x$

Required

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$\frac{1}{6}x + \frac{1}{3} = \frac{2}{3}x$

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$\frac{1}{6}x - \frac{2}{3}x = - \frac{1}{3}$

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$\frac{-3x}{-3}= \frac{-2}{-3}$

$x= \frac{2}{3}$

Hence, the number is $\frac{2}{3}$

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Step-by-step explanation:

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Step-by-step explanation:

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