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Delvig [45]
4 years ago
12

What is the frequency of oscillation for a mass on the end of spring with a period of motion of 2.6 seconds? Calculate answer to

one decimal place.
Physics
1 answer:
Tcecarenko [31]4 years ago
4 0

Answer:

Frequency, f = 0.38 Hz

Explanation:

Time period of the spring, T = 2.6 seconds

We need to find the frequency of oscillation for a mass on the end of spring. The relation between the time period and the frequency is given by :

Let f is the frequency of oscillation. So,

f=\dfrac{1}{T}

f=\dfrac{1}{2.6\ s}

f = 0.38 Hz

or

f = 0.4 Hz

So, the frequency of oscillation for a mass on the end of a spring is 0.38 hertz. Hence, this is the required solution.

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Two masses are joined by a mass less string. A 33-N force applied vertically to the upper mass gives the system a constant upwar
lisov135 [29]

Lower mass: 1.20 kg, upper mass: 1.28 kg

Explanation:

In order to solve the problem, we consider the forces acting on the upper mass only first.

The upper mass is acted upon three forces:

  • The applied force F_a=33 N, upward
  • The weight of the mass itself, m_u g, where m_u is the upper mass and g=9.8 m/s^2 is the acceleration of gravity, downward
  • The tension in the string, T=16 N, downward

Therefore, the equation of the forces for the upper mass is:

F_a - m_u g - T = m_u a

where

a=3.5 m/s^2 is the acceleration (upward)

Solving for m_u,

m_u = \frac{F_a-T}{a+g}=\frac{33-16}{3.5+9.8}=1.28 kg

Now we can find the lower mass by considering the forces acting on it:

  • The tension in the string, T = 16 N, upward
  • The weight of the mass itself, m_L g, where m_L is the lower mass, downward

So the equation of the forces is

T-m_L g = m_L a

And solving for the mass,

m_L = \frac{T}{a+g}=\frac{16}{3.5+9.8}=1.20 kg

Learn more about acceleration and forces:

brainly.com/question/11411375

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#LearnwithBrainly

7 0
3 years ago
A pair of adult nitwits sit balanced on a teeter totter type device. One of them, whose mass is 54.2 kg, is 1.20 m from the poin
andreev551 [17]

Answer:

The mass of the second person is 28.91 kg

Explanation:

Given;

mass of the first adult, m₁ = 54.2 kg

distance of the first adult from the point of balance, x = 1.20 m

mass of the second adult, = m₂

distance of the second adult from the point of balance, y = 2.25 m

Taking moment about the point of balance, we will have

m₁x = m₂y

54.2 x 1.2 = 2.25y

2.25y = 65.04

y = 65.04/2.25

y = 28.91 kg

Therefore, the mass of the second person is 28.91 kg

3 0
4 years ago
Read 2 more answers
which is heavier, a one ton box or a one metric ton box? How many pounds heavier is one than the other?
arsen [322]

-- 1 ton is defined as 2,000 pounds.
-- 1 metric ton (or tonne) is defined as 1,000 kilograms of mass.

On Earth,1,000 kilograms of mass weigh 2,204.6 pounds ... 204.6 pounds
more than 1 ton.

On, say, the moon, however, 1,000 kilograms of mass weigh
only 364.9 pounds ... about 18% of 1 ton.


7 0
4 years ago
Complete the following table. Be sure to include units in your answer.
mel-nik [20]

Answer:

Complete the following table. Be sure to include units in your answer.

Explanation:

all you have to do is mautiply them

6 0
3 years ago
PLZZZ I will give brainliest. A ball that contains mechanical energy is rolled across the floor. You notice the ball is slowing
Oksanka [162]

Answer: because of friction it will stop rolling completly

Explanation:

8 0
3 years ago
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