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2 years ago

According to Ohm's law what would happen if the current was increased and the resistance was held constant?

1 answer:

6 0

Ohm's law deals with the relation between voltage and current in an ideal conductor. It states that: Potential difference across a conductor is proportional to the current that pass through it. It is expressed as V=IR. Therefore, the correct answer is option B, the voltage would increase as well.

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Un resorte se alarga 5 cm bajo la acción de una fuerza de 39,2 N. ¿Cuál es la constante del resorte? Si ahora la fuerza es 68,6

Lorico [155]

Answer:

$k=784 N/m$

$\Delta x=8,8 cm$

Explanation:

Usando la ley de Hook tenemos:

$F=k\Delta x$

Solving it for k we have:

$k=\frac{F}{\Delta x}$

$k=\frac{39,2}{0,05}$

$k=784 N/m$

Usando la misma ecuación y sabiendo k tenemos:

$\Delta x=\frac{F}{k}$

$\Delta x=\frac{68,6}{784}$

$\Delta x=8,8 cm$

Espero esto te ayude!

6 0

2 years ago

Does air play a role in the propagation of the human voice from one end of a lecture hall to the other

love history [14]

Answer: Yes

Air serves as a propagation medium.

Explanation:

Propagation of sound wave require a medium for transmission. Sound is produced by vibrating objects, The matter or substance through which sound is transmitted is called a medium. It can be solid, liquid or gas. Therefore to propagate sounds (human voice) from one end of a lecture hall to the other we need a propagation medium which is air. Air serves as a propagation medium.

4 0

3 years ago

What is the acceleration of the object in the graph?

viktelen [127]

Answer:

-0.8 m/s²

Explanation:

Acceleration is the slope of a velocity vs. time graph.

a = Δv / Δt

a = (0 m/s − 12 m/s) / (15 s − 0 s)

a = -0.8 m/s²

3 0

2 years ago

How many photons will be required to raise the temperature of 1.8 g of water by 2.5 k ?'?

tatyana61 [14]

Missing part in the text of the problem:
"Water is exposed to infrared radiation of wavelength 3.0×10^−6 m"

First we can calculate the amount of energy needed to raise the temperature of the water, which is given by
$Q=m C_s \Delta T$
where
m=1.8 g is the mass of the water
$C_s = 4.18 J/(g K)$ is the specific heat capacity of the water
$\Delta T=2.5 K$ is the increase in temperature.

Substituting the data, we find
$Q=(1.8 g)(4.18 J/(gK))(2.5 K)=18.8 J=E$

We know that each photon carries an energy of
$E_1 = hf$
where h is the Planck constant and f the frequency of the photon. Using the wavelength, we can find the photon frequency:
$\lambda = \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{3 \cdot 10^{-6} m}=1 \cdot 10^{14}Hz$

So, the energy of a single photon of this frequency is
$E_1 = hf =(6.6 \cdot 10^{-34} J)(1 \cdot 10^{14} Hz)=6.6 \cdot 10^{-20} J$

and the number of photons needed is the total energy needed divided by the energy of a single photon:
$N= \frac{E}{E_1}= \frac{18.8 J}{6.6 \cdot 10^{-20} J} =2.84 \cdot 10^{20} photons$

4 0

3 years ago

A factory has 1200 workers of which 720 are male and the rast are female what percent of workers are female

umka21 [38]

Answer:

Percent of Female Workers = 40%

Explanation:

The percentage of the female workers in the given group of workers can be easily found by the following formula:

$Percent\ of\ Female\ Workers = \frac{No.\ of\ Female\ Workers}{Total\ No.\ of\ Workers}\ x\ 100\%$

where,

Total No. of Workers = 1200

No. of Female Workers = Total Workers - No. of Male Workers

No. of Female Workers = 1200 - 720 = 480

Therefore,

$Percent\ of\ Female\ Workers = \frac{480}{1200}\ x\ 100\%$

Percent of Female Workers = 40%

7 0

2 years ago