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raketka [301]
3 years ago
5

The following set of coordinates represents which figure? (0, 4), (0, 7), (1, 5), (1, 2)

Mathematics
2 answers:
BigorU [14]3 years ago
7 0

Answer with explanation:

The Coordinates of four points in two dimensional plane is  (0, 4), (0, 7), (1, 5), (1, 2).

Point (0,4) and point (0,7) lies on y axis.

And point (1,5) and point (1,2) lies in First Quadrant.

If you will join these four points , we will get a Quadrilateral, as it consist of four distinct line segments ,ends being joined with one another.

We can also check this by plotting the points in Two dimensional coordinate plane.

Marking, the points as  A(0, 4), B(0, 7), C(1, 5), D(1, 2).

We will check which kind of Quadrilateral is this

1. Parallelogram

2. Rhombus

3. Rectangle

4. Square

5. Kite

6. Trapezium

We will use distance formula to find the length of sides of Quadrilateral.

Distance formula

=\sqrt{({x_{2}-x_{1})^2+(y_{2}-y_{1})^2}}\\\\ AB=\sqrt{(0-0)^2+(7-4)^2} =3\\\\ BC=\sqrt{(1-0)^2+(5-7)^2}=\sqrt{1+4}\\\\ BC=\sqrt{5}\\\\ CD=\sqrt{(1-1)^2+(5-2)^2}=3\\\\ DA=\sqrt{(1-0)^2+(4-2)^2}\\\\ DA=\sqrt{5}

Length of Opposite sides are equal. So,it can be parallelogram or Rectangle.

Now, we will find the length of Diagonal.

AC=\sqrt{(1-0)^2+(5-4)^2}\\\\ AC=\sqrt{2} \\\\ BD=\sqrt{(1-0)^2+(7-2)^2}\\\\ BD=\sqrt{1+25}\\\\ BD=\sqrt{26}

Length of Diagonal is not equal, but opposite sides are equal.

So, the given Quadrilateral is Parallelogram.

Romashka [77]3 years ago
6 0

Answer:

The figure represent a parallelogram

Step-by-step explanation:

we have

(0, 4), (0, 7), (1, 5), (1, 2)

using a graphing tool

Plot the points

see the attached figure  

The figure has opposite sides parallel and equal in length

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The local branch of the Internal Revenue Service spent an average of 21 minutes helping each of 10 people prepare their tax retu
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Answer:

The confidence Interval is [- 0.7053  10.4521]

a: The  hypotheses  are

H0: μ1=μ2    against the claim Ha :μ1≠μ2

b. The critical value for t∝/2 for 17 d.f  t > 2.508 and  t < -2.111

c. t= -2.8422

d. The calculated value of t= -2.8422 is less than t < -2.11 the critical value therefore we reject H0 and conclude there is a difference between the two means.

Step-by-step explanation:

When the standard deviations are not the same then the confidence intervals for mean differences are calculated as

(x1`-x2`)- t∝/2 √s1²/n1 + s2²/n2 < u1-u2 < (x1`-x2`)+ t∝/2 √s1²/n1 + s2²/n2

x1`= 21        x2`= 27

n1=  10       n2= 14

s1= 5.6       s2= 4.3

The degrees of freedom is calculated using

υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

= 17

The t∝/2 for 17 d.f = 2.11

Putting the values

(x1`-x2`)- t∝/2 √s1²/n1 + s2²/n2 < u1-u2 < (x1`-x2`)+ t∝/2 √s1²/n1 + s2²/n2

(21-27) - 2.11√5.6²/10+ 4.3²/14 < u1-u2 <(21-27)  +2.11√5.6²/10+4.3²/14

6- 2.11*2.111 < u1-u2 <  ( 6 )  +2.11*2.111

6- 4.4521 < u1-u2 <  ( 6 )  +5.294

- 1.5479 < u1-u2 <  10.4521

The confidence Interval is [- 0.7053  10.4521]

a: The  hypotheses  are

H0: μ1=μ2    against the claim Ha :μ1≠μ2

The claim is that there is a difference in the average time spent by the two services

b. The critical value for t∝/2 for 17 d.f  t > 2.508 and  t < -2.111

The degrees of freedom is calculated using

υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

= 17

c. The test statistic is

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t= (21-27)  /√5.6²/10+ 4.3²/14

t= -6/2.111

t= -2.8422

d. The calculated value of t= -2.8422 is less than t < -2.11 the critical value therefore we reject H0 and conclude there is a difference between the two means.

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