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Marina86 [1]
3 years ago
13

PLEASE HELP

Mathematics
2 answers:
Inga [223]3 years ago
4 0
<h3>Answer: The scale factor is 5 used to create the dilation.</h3>

Step-by-step explanation: We are given original image ABCD.

The coordinates of the image ABCD are

A (1, 2)

B ( 2, 2)

C ( 2, 1)

D ( 1, 1).

And coordinates of dilated image A'B'C'D' are :

A' (5, 10)

B' ( 10, 10)

C' ( 10, 5)

D' ( 5, 5).

We can see that (x,y) --> (5x, 5y) rule is being applied there.

<em>Therefore, each x and y-coordinate is being multiplied by 5.</em>

<h3>Therefore, the scale factor 5 is used to create the dilation.</h3>
Rama09 [41]3 years ago
3 0
<span>image ​ A′B′C′D′ is 5 times bigger than pre-image ABCD

scale factor = 5</span>
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Which of the following is not a correct name for the line shown?
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Answer:

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Step-by-step explanation:

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Consider all options:

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A group of marketing students at a large university wants to determine the proportion of first year students who use certain typ
GREYUIT [131]

The required sample size is 694.

Given a student wants to make a guess within 0.03 of the true ratio with a 95% confidence level.

Margin of Error, E = 0.03

significance level α=0.05  {95% confidence}

A given estimate of the percentage of population p is p = 0.79.

The critical value for the significance level α = 0.05 is Zc = 1.96. This can be determined using either Excel or a normal probability table.

Use the following formula to calculate the minimum sample size required to estimate the percentage of population p within the required margin of error.

n≥p(1-p)(Zc÷E)²

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n=693.1016

Therefore, the  resample sizequired to meet the condition is n ≥ 693.1016 and must be an integer. From this, we conclude that the minimum sample size required is n = 694.

Learn more about confidence level from here brainly.com/question/23630128

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2 years ago
The population of a community is known to increase at a rate proportional to the number of people present at time t. The initial
qaws [65]

Answer:

Step-by-step explanation:

Let P be the population of the community

So the population of a community increase at a rate proportional to the number of people present at a time

That is

\frac{dp}{dt} \propto p\\\\\frac{dp}{dt} =kp\\\\ [k \texttt {is constant}]\\\\\frac{dp}{dt} -kp =0

Solve this equation we get

p(t)=p_0e^{kt}---(1)

where p is the present population

p₀ is the initial population

If the  initial population as doubled in 5 years

that is time t = 5 years

We get

2p_o=p_oe^{5k}\\\\e^{5k}=2

Apply In on both side to get

Ine^{5k}=In2\\\\5k=In2\\\\k=\frac{In2}{5} \\\\\therefore k=\frac{In2}{5}

Substitute k=\frac{In2}{5}  in p(t)=p_oe^{kt} to get

\large \boxed {p(t)=p_oe^{\frac{In2}{5}t }}

Given that population of a community is 9000 at 3 years

substitute t = 3 in {p(t)=p_oe^{\frac{In2}{5}t }}

p(3)=p_oe^{3 (\frac{In2}{5}) }\\\\9000=p_oe^{3 (\frac{In2}{5}) }\\\\p_o=\frac{9000}{e^{3(\frac{In2}{5} )}} \\\\=5937.8

<h3>Therefore, the initial population is 5937.8</h3>
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What is the answer for what x equals
Yuliya22 [10]

Answer:

Im not good at shapes and geometry but what i can tell u is that x = 1 so whenever u get ur area or whatever you can multiply it by one and thats what your answer is.

Step-by-step explanation:

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