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torisob [31]
3 years ago
10

-2x+6=30-6x. -6,6,-8,8

Mathematics
1 answer:
Illusion [34]3 years ago
4 0
-2x + 6 = 30 - 6x
--> -2x + 6x = 30 - 6
<span>--> 4x = 24
</span><span>--> x = 24/4
</span><span>--> x = 6</span>
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Suppose that 50% of all young adults prefer McDonald's to Burger King when asked to state a preference. A group of 12 young adul
ddd [48]

Answer:

a) 0.194 = 19.4% probability that more than 7 preferred McDonald's

b) 0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred McDonald's

c) 0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred Burger King

Step-by-step explanation:

For each young adult, there are only two possible outcomes. Either they prefer McDonalds, or they prefer burger king. The probability of an adult prefering McDonalds is independent from other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

50% of all young adults prefer McDonald's to Burger King when asked to state a preference.

This means that p = 0.5

12 young adults were randomly selected

This means that n = 12

(a) What is the probability that more than 7 preferred McDonald's?

P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{12,8}.(0.5)^{8}.(0.5)^{4} = 0.121

P(X = 9) = C_{12,9}.(0.5)^{9}.(0.5)^{3} = 0.054

P(X = 10) = C_{12,10}.(0.5)^{10}.(0.5)^{2} = 0.016

P(X = 11) = C_{12,11}.(0.5)^{11}.(0.5)^{1} = 0.003

P(X = 12) = C_{12,12}.(0.5)^{12}.(0.5)^{0} = 0.000

P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) = 0.121 + 0.054 + 0.016 + 0.003 + 0.000 = 0.194

0.194 = 19.4% probability that more than 7 preferred McDonald's

(b) What is the probability that between 3 and 7 (inclusive) preferred McDonald's?

P(3 \leq X \leq 7) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.054

P(X = 4) = C_{12,4}.(0.5)^{4}.(0.5)^{8} = 0.121

P(X = 5) = C_{12,5}.(0.5)^{5}.(0.5)^{7} = 0.193

P(X = 6) = C_{12,6}.(0.5)^{6}.(0.5)^{6} = 0.226

P(X = 7) = C_{12,7}.(0.5)^{7}.(0.5)^{5} = 0.193

P(3 \leq X \leq 7) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) = 0.054 + 0.121 + 0.193 + 0.226 + 0.193 = 0.787

0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred McDonald's

(c) What is the probability that between 3 and 7 (inclusive) preferred Burger King?

Since p = 1-p = 0.5, this is the same as b) above.

So

0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred Burger King

7 0
3 years ago
2x+3 what is x I don’t know
Triss [41]

Answer:

2x + 3 \\  or \: 2x =  - 3 \\ or \: x =   - \frac{3}{2}  \\ therefore \:  \: the \: value \: of \: x \: is \:  -  \frac{3}{2}

<h3> I hoped this helps you ☺️☺️ </h3>

Thank you ☺️☺️

8 0
3 years ago
Bob has a set of 10 colored markers in a backpack. One is yellow and one is blue. What is the probability Bob will reach into th
11111nata11111 [884]
4/8 because if 2 already got pulled theres only 8 left four blue four yellow theres a 4 out od 8 chance youll pull them like that again

3 0
3 years ago
Read 2 more answers
Function g can be thought of as a translation (shifted) version of f(x)=x^2
dimaraw [331]

Answer:

(x+5)²

Step-by-step explanation:

To solve this we just need to shift the graph 5 spots to the left

to do this we need to add 5 to the x

(x+5)²

5 0
3 years ago
Find the difference of(ab+8a+1)-(-6ab+4)
vagabundo [1.1K]
Hey there!

When finding the difference of expressions like these, there's a few things you should keep in mind. 

1. When finding the difference of two polynomials, multiply the polynomial that implied to be "negative" by –1 to expand the problem and make it easier to solve. 

2. You combine terms based on their unknown terms, like x, y, x², ab, etc. You cannot combine the terms x and x², but you can combine the terms 6b and 8b by adding them. 

3. You can rearrange your terms however you see fit. If a polynomial is implied as "positive", you can multiply that entire polynomial by +1 to get rid of the parentheses. 

With all that in mind, you can go ahead and solve for your difference, like so:

(ab+8a+1)-(-6ab+4)

(ab+8a+1) (-1(-6ab+4))

(ab+8a+1) + (6ab-4)

ab+6ab+8a+1-4

7ab+8a-3

7ab+8a-3 will be your difference. 

Hope this helped you out! :-)
8 0
3 years ago
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