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Pavel [41]
3 years ago
13

Considering that catalysts are not consumed in a reaction, how do you think increasing the amount of catalyst would affect the r

eaction rate for the decomposition of hydrogen peroxide?
Chemistry
2 answers:
ira [324]3 years ago
6 0
Answer : If you add catalyst to a reaction mixture it would increase its rate of reaction to certain extent after sometime the reactant molecules will start regenerating the catalyst molecule again. There will be one moment where reactant molecule will not require any more catalyst and on their own they will do the reaction. The main function of catalyst is to lower the activation energy of the reaction irrespective of decomposition or generation of any product.
Akimi4 [234]3 years ago
4 0

Answer: by lowering the activation energy

Explanation:

A catalyst is a substance which increases the rate of a reaction by taking the reaction through a different path which involves lower activation energy and thus more molecules can cross the energy barrier and convert to products.

Activation energy is the extra energy that must be supplied to reactants in order to cross the energy barrier and thus convert to products.

The catalyst itself does not take part in the chemical reaction and is regenerated as such at the end.

Thus the rate for the decomposition of hydrogen peroxide increases on addition of catalyst by lowering the activation energy.

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The element that appears farthest to the is written first in the chemical name of a covalent compound.
Mashcka [7]

Answer: left

Explanation: The element that appears farthest to the

✔ left

is written first in the chemical name of a covalent compound.

3 0
3 years ago
Is this right??? If not gimme da right answer plz
NemiM [27]

Answer:

yeah

Explanation:

well, probably. they kicked me out of math class because I put a live chicken in the classroom and it pooped everywhere, so I had to clean it up and bring it back where I found it (which is the side of the road.)

3 0
3 years ago
Read 2 more answers
How many neutrons does beryllium have?
PilotLPTM [1.2K]
5.

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6 0
2 years ago
Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial ch
Salsk061 [2.6K]

Answer:

kp= 3.1 x 10^(-2)

Explanation:

To solve this problem we have to write down the reaction and use the ICE table for pressures:

                                2SO2      +        O2         ⇄              2SO3

Initial                      3.4 atm           1.3 atm                         0 atm

Change                    -2x                    - x                                + 2x

Equilibrium            3.4 - 2x            1.3 -x                          0.52 atm

In order to know the x value:

2x = 0.52

x=(0.52)/2= 0.26

                               2SO2             +          O2              ⇄              2SO3

Equilibrium        3.4 - 0.52                1.3 - 0.26                     0.52 atm

Equilibrium        2.88 atm                 1.04 atm                      0.52 atm

with the partial pressure in the equilibrium, we can obtain Kp.

Kp=\frac{PSO3^2}{PSO2^2 PO2}=\frac{(0.52)^2}{(2.88)^2(1.04)}=0.03135

8 0
3 years ago
What does Hess's law state can be done in order to be able to react solid magnesium with oxygen gas safely (that is, without exp
aleksley [76]

Answer:

C. The reaction can be broken down and performed in steps

Explanation:

Hess's Law of Constant Heat Summation states that irrespective of the number of steps followed in a reaction, the total enthalpy change for the reaction is the sum of all enthalpy changes corresponding to all the steps in the overall reaction. The implication of this law is that  the change of enthalpy in a chemical reaction is independent of the pathway between the initial and final states of the system.

To obtain MgO safely without exposing magnesium to flame, the reaction sequence shown in the image attached may be carried out. Since the enthalpy of the overall reaction is independent of the pathway between the initial and final states of the system, the sum of the enthalpy of each step yields the enthalpy of formation of MgO.

3 0
2 years ago
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