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Pavel [41]
3 years ago
13

Considering that catalysts are not consumed in a reaction, how do you think increasing the amount of catalyst would affect the r

eaction rate for the decomposition of hydrogen peroxide?
Chemistry
2 answers:
ira [324]3 years ago
6 0
Answer : If you add catalyst to a reaction mixture it would increase its rate of reaction to certain extent after sometime the reactant molecules will start regenerating the catalyst molecule again. There will be one moment where reactant molecule will not require any more catalyst and on their own they will do the reaction. The main function of catalyst is to lower the activation energy of the reaction irrespective of decomposition or generation of any product.
Akimi4 [234]3 years ago
4 0

Answer: by lowering the activation energy

Explanation:

A catalyst is a substance which increases the rate of a reaction by taking the reaction through a different path which involves lower activation energy and thus more molecules can cross the energy barrier and convert to products.

Activation energy is the extra energy that must be supplied to reactants in order to cross the energy barrier and thus convert to products.

The catalyst itself does not take part in the chemical reaction and is regenerated as such at the end.

Thus the rate for the decomposition of hydrogen peroxide increases on addition of catalyst by lowering the activation energy.

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A 0.1510 gram sample of a hydrocarbon produces 0.5008 gram CO2 and 0.1282 gram H2O in combustion analysis. Its
Over [174]
In a combustion of a hydrocarbon compound, 2 reactions are happening per element:

C + O₂ → CO₂
2 H + 1/2 O₂ → H₂O

Thus, we can determine the amount of C and H from the masses of CO₂ and H₂O produced, respectively.

1.) Compute for the amount of C in the compound. The data you need to know are the following:
Molar mass of C = 12 g/mol
Molar mass of CO₂ = 44 g/mol
Solution:
0.5008 g CO₂*(1 mol CO₂/ 44 g)*(1 mol C/1 mol CO₂) = 0.01138 mol C
0.01138 mol C*(12 g/mol) = 0.13658 g C

Compute for the amount of H in the compound. The data you need to know are the following:
Molar mass of H = 1 g/mol
Molar mass of H₂O = 18 g/mol
Solution:
0.1282 g H₂O*(1 mol H₂O/ 18 g)*(2 mol H/1 mol H₂O) = 0.014244 mol H
0.014244 mol H*(1 g/mol) = 0.014244 g H

The percent composition of pure hydrocarbon would be:
Percent composition = (Mass of C + Mass of H)/(Mass of sample) * 100
Percent composition = (0.13658 g + 0.014244 g)/(<span>0.1510 g) * 100
</span>Percent composition = 99.88%

2. The empirical formula is determined by finding the ratio of the elements. From #1, the amounts of moles is:

Amount of C = 0.01138 mol
Amount of H = 0.014244 mol

Divide the least number between the two to each of their individual amounts:
C = 0.01138/0.01138 = 1
H = 0.014244/0.01138 = 1.25

The ratio should be a whole number. So, you multiple 4 to each of the ratios:
C = 1*4 = 4
H = 1.25*4 = 5

Thus, the empirical formula of the hydrocarbon is C₄H₅.

3. The molar mass of the empirical formula is

Molar mass = 4(12 g/mol) + 5(1 g/mol) = 53 g/mol
Divide this from the given molecular weight of 106 g/mol
106 g/mol / 53 g/mol = 2
Thus, you need to multiply 2 to the subscripts of the empirical formula.

Molecular Formula = C₈H₁₀

4 0
3 years ago
Is ok2 gas a element compound or homogeneous or heterogeneous mixture?
ivolga24 [154]
I'm guessing you mean O2 gas? This is an elemental compound. It can't be a mixture because it is composed of only 1 element. Hope I helped!
4 0
3 years ago
A K+ ion is similar to a Cl– ion in that they both have the same A) nuclear charge B) number of electrons C) atomic number D) nu
pshichka [43]

Answer:

B) number of electrons

Explanation:

The two species:

          K+   and Cl- have the same number of electrons.

A neutral atom of K has 19 electrons

A neutral atom of Cl has 17 electrons

Now,

 To form K+, K will have to lose an electron and then the number of electrons becomes 18

To form Cl-, Cl will have to gain an electrons and then the number of electrons becomes 18

So, therefore, the number of electrons on both species is 18

3 0
3 years ago
Explain why there was a reaction between zinc metal and a salt solution of copper sulphate please help me​
natali 33 [55]

Answer:

When zinc is added to copper sulphate (CUSO4) solution due to more reactivity of zinc, cooper is replaced by the zinc and forms zinc sulphate. During the process, the colour of the solution changes from blue to colourless.

6 0
3 years ago
Example of electrovalent bond​
olchik [2.2K]

Explanation:

<h3>MgCl2, CaCl2, MgO, Na2S, CaH2, AlF3, NaH, KH, K2O, KI, RbCl, NaBr, CaH2 etc.</h3>

<h2>hope it helps.</h2><h2>stay safe healthy and happy..</h2>
4 0
3 years ago
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