<em>Acetic acid, HC2H3O2</em>
First, calculate for the molar mass of acetic acid as shown below.
M = 1 + 2(12) + 3(1) + 2(16) = 60 g
Then, calculating for the percentages of each element.
<em> Hydrogen:</em>
P1 = ((4)(1)/60)(100%) = <em>6.67%</em>
<em> Carbon:</em>
P2 = ((2)(12)/60)(100%) = <em>40%</em>
<em>Oxygen</em>
P3 =((2)(16) / 60)(100%) = <em>53.33%</em>
<em>Glucose, C6H12O6</em>
The molar mass of glucose is as calculated below,
6(12) + 12(1) + 6(16) = 180
The percentages of the elements are as follow,
<em> Hydrogen:</em>
P1 = (12/180)(100%) = <em>6.67%</em>
<em>Carbon:</em>
P2 = ((6)(12) / 180)(100%) = <em>40%</em>
<em>Oxygen:</em>
P3 = ((6)(16) / 180)(100%) = <em>53.33%</em>
b. Since the empirical formula of the given substances are just the same and can be written as CH2O then, the percentages of each element composing them will just be equal.
Based on the observations from, the substance that water is more attracted to are polar substances.
<h3>
What is the Polarity of water?</h3>
Water is a compound made up of 2 atoms of hydrogen and 1 atom of oxygen.
Water molecule is polar due to the unequal sharing of electrons between the atoms and the unsymmetrical shape of the molecule.
Since water molecules are polar, they are more attracted to molecules that are also polar.
Thus, based on the observations from, the substance that water is more attracted to are polar substances.
Learn more about water here: brainly.com/question/5060579
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Mass=volume x density
if we have mass and density we can calculate volume using the formula: volume=mass/density
volume of the displaced water = 600g/19.3g/cm3
volume = 31.09cm3
We need to find the Ka value of HF. First, set up the balanced chemical equation:
HF ===> H+ + F-
The formula for the Ka value of an acid is
Ka = [concentration of products] / [concentration of reactants]
Ka = [H+] [F-} / [HF]
So if we are given the concentration of the products and reactants, we will be able to solve for the Ka value of HF.
Sulfide would be an AWNSER but
