Which wind belt do we live in
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The acid dissociation constant (Ka) defines the difference between a weak and a strong acid. The % ionization of hypochlorous acid is 0.14%.
<h3>What is the acid dissociation constant?</h3>The acid dissociation constant is used to define the ionization constant of an acidic substance. It gives the quantitative measurement of the strength.
The ICE table is attached to the image below.
The acid dissociation constant (Ka) for the reaction is,
Ka = [H⁺][ClO⁻] ÷ [HClO]
= a² ÷ (0.015 - a)
= 3.0 x 10⁻⁸
Now, a² + 3.0 x 10⁻⁸ a - 4.5 × 10⁻¹⁰ = 0
So, a = 2.210 × 10⁻⁵
Solving further,
[H+] = a = 2.210 × 10⁻⁵ M
The percent ionization is calculated as,
[H+] ÷ [HClO] × 100
= 2.210 × 10⁻⁵ M ÷ 0.015 × 100
= 0.14 %
Therefore, 0.14 % is the percentage of hypochlorous ionization.
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Your question is incomplete, but most probably your full question was, The ka of hypochlorous acid (HClO) is 3.0 x 10⁻⁸ at 25.0°C. What is the % of ionization of hypochlorous acid in a 0.015 aqueous solution of HClO at 25.0C?
The mole fraction of pentane in the vapor is 0.291
Vapour pressure rises with temperature and is a measurement of a substance's propensity to transform into a gaseous or vapour state. The boiling point of a liquid is the temperature at which the pressure exerted by its surroundings equals the vapour pressure present at the liquid's surface.
The number of moles of a particular component in the solution divided by the overall number of moles in the sample solution is known as the mole fraction.
Using the formula for vapour pressure,
vapour pressure = °
×
+
°
×
vapour pressure = 151 × + 425 ×
240 = 151 - 151 + 425
240 - 151 = - 151 + 425
89 = 274
=
0.291 =
Therefore, the mole fraction of pentane in the vapor is 0.291
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