<u>Answer:</u> The final concentration of 
is 0.019767 M
<u>Explanation:</u>
Molarity is calculated by using the equation:
Initial moles of = 0.3 moles
Volume of solution = 3.1 L
For the given chemical equation:
<u>Initial:</u> 0.097
<u>At eqllm:</u> 0.097-x x x
The expression of 
for above equation follows:
![K_c=\frac{[POCl][Cl_2]}{[POCl_3]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BPOCl%5D%5BCl_2%5D%7D%7B%5BPOCl_3%5D%7D)
We are given:
Putting values in above expression, we get:
Neglecting the negative value of 'x' because concentration cannot be negative.
So, final concentration of = (0.097 - x) = (0.097 - 0.077233) = 0.019767 M
Hence, the final concentration of is 0.019767 M
I think it's 65.3342 grams
32 electrons. as the orbitals get father away from the nucleus, they hold more electrons.
Answer:
The reaction of one mole of oxygen (O2) releases 445 kJ of energy.
Explanation:
Firstly, the reaction is exothermic since the sign of enthalpy change ΔH is negative.
The balanced equation: CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l): ΔH = −890 kJ,
Shows that 1 mole of CH₄ react with 2 moles of oxygen and releases 890 kJ.
So, every choice says that absorb is wrong (choice 1& 3).
Choice no. 4 is wrong since it says that 2 moles of methane releases 890 kJ, because only one mole release this amount of energy.
So, the right choice is The reaction of one mole of oxygen (O2) releases 445 kJ of energy.
