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Rasek [7]
4 years ago
6

When the pH of a solution is 12.83, what is [H+]

Chemistry
2 answers:
ra1l [238]4 years ago
8 0
Answer:

There are <span>1.479×<span>10<span>−13</span></span></span> concentration of hydrogen ions <span>mo<span>lL</span></span>.

Explanation:

Because pH is a logarthmic scale, we can use the formula: <span><span>[<span>H+</span>]</span>=<span>10-pH</span></span>. Where...
=> <span>[<span>H+</span>]</span> is the concentration of hydrogen ions in the solution.
=> <span>pH</span> is the pH of the solution. 
=> Where 10 is the base of the power - it's a logarithm formula.

We can now just sub in the values and solve for [<span><span>H+</span>]</span>.

<span><span><span>[<span>H+</span>]</span>=<span>10-pH</span></span><span><span>=<span>10<span>−<span>(12.83)</span></span></span></span><span>=1.479108388×<span>10<span>−13</span></span></span></span></span>

We can round (if required) to <span>1.479×<span>10<span>−13</span></span></span>.

Thus, there are <span>1.479×<span>10<span>−13</span></span></span> concentration of hydrogen ions <span><span>mol</span>L</span>.

Hope this helps :)

stepladder [879]4 years ago
3 0

Answer: 1.5 × 10–13M

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Explain how balanced and unbalanced forces affect an object's motion differently.
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3 years ago
A sample compound contains 9.11 g Ni and 5.89g F. What is the empirical formula of this compound?
Alexxx [7]

The empirical formula of the compound is C. NiF₂.

<em>Step 1</em>. Calculate the <em>moles of each element</em>

The empirical formula is the simplest whole-number ratio of atoms in a compound.

The ratio of atoms is the same as the ratio of moles.

So, our job is to calculate the molar ratio of Ni to F.

Moles of Ni = 9.11 g Ni × (1 mol Ni /(58.69 g Ni) = 0.1552 mol Ni

Moles of F = 5.89 g F × (1 mol F/19.00 g F) = 0.3100 mol F

<em>Step 2</em>. Calculate the <em>molar ratio</em> of the elements

Divide each number by the smallest number of moles

Ni:F = 0.1552:0.3100 = 1:1.997 ≈ 1:2

<em>Step 3</em>: Write the <em>empirical formula</em>

EF = NiF₂

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Pure substances contain only one type of a. Atoms only. B. Molecules only. C. Atoms or molecules. D. Mixture.
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A. Atoms only. An element cannot be separated into simpler materials
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Which has higher specific heat capacity, iron or brick (Concrete
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2. (8 pts) Boric acid (H3BO3) has three hydrogens in a molecule, but effectively acts as a monoprotic acid (Ka = 5.8∙10-10), sin
Andrew [12]

Answer:

7.85 g H₃BO₃

2.92 g NaOH

Explanation:

The strategy for solving this question is to first utilize the Henderson- Hasselbach equation to calculate the ratio of conjugate base concentration to weak acid:

pH = pKa + log [A⁻]/ [HA]

In this case:

pH = pKa + log [H₂BO₃⁻]/[H₃BO₃]

We know pH and indirectly pKa ( = - log Ka ).

9.00 = -log(5.8 x 10⁻¹⁰) + log [H₂BO₃⁻]/[H₃BO₃]

9.00 = 9.24 + log [H₂BO₃⁻]/[H₃BO₃]

log [H₂BO₃⁻]/[H₃BO₃] = - 0.24

taking inverse log function to both sides of the equation:

[H₂BO₃⁻]/[H₃BO₃]  = 10^-0.24 = 0.58

We are also told we want to have a total concentration of boron of 0.200 mol/L, and if we call x the concentration of  H₂BO₃⁻ and y the concentration of H₃BO₃, it follows that:

x + y = 0.200 ( since we have 1 Boron atom per formula of each compound)

and from the Henderson Hasselbach calculation, we have that

x / y = 0.58

So we have a system of 2 equations with two unknowns, which when solved give us that

x = 0.073  and y = 0.127

Because we are told the volume is one liter it follows that the number of moles of boric acid and the salt are the same numbers 0.073 and 0.127

gram boric acid = 0.127 mol x molar mass HBO₃ = 0127 mol x 61.83 g/mol

                          = 7.85 g boric acid

grams NaOH = 0.073 mol x molar mass NaOH = 0.073 x 40 g/mol

                          = 2.92 g NaOH

4 0
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