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4 years ago

15

Why does the multimeter reading decrease as the frequency increases?

1 answer:

Lynna [10]4 years ago

7 0

<span>Multimeter circuit are designed to measure 60 c/s or 400 c/s AC. It has quite large bypass capacitance to limit the input frequency response to avoid osillation. Most digital AC volt meter shall not give accurate reading more than 2000 c/s. That is why your ordinary AC multimeter does not response to higher frequency.</span>

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A motor does 1000J of work in 18 seconds. What is the power of the<br> motor?

solong [7]

Answer:

55.56 watt

Explanation:

Work (W) = 1000 J

time (T) = 18 sec

power (P) = ?

We know power is the rate of doing work so

p = w / t

= 1000 / 18

= 55. 56 watt

7 0

3 years ago

Light of wavelength 650 nm is normally incident on the rear of a grating. The first bright fringe (other than the central one) i

koban [17]

Answer:

A

$N = 1340.86 \ slits / cm$

B

$\theta = 15.7^o$

Explanation:

From the question we are told that

The wavelength is $\lambda = 650 \ nm = 650 *10^{-9} \ m$

The angle of first bright fringe is $\theta = 5^o$

The order of the fringe considered is n =1

Generally the condition for constructive interference is

$dsin (\theta ) = n * \lambda$

=> $d = \frac{1 * 650 *10^{-9 }}{ sin(5)}$

=> $d = 7.458 *10^{-6} \ m$

Converting to cm

$d = 7.458 *10^{-6} \ m = 7.458 *10^{-6} * 100 = 0.0007458 \ cm$

Generally the number of grating pre centimeter is mathematically represented as

$N = \frac{1}{d}$

=> $N = \frac{1}{0.0007458}$

=> $N = 1340.86 \ slits / cm$

Considering question B

From the question we are told that

The first wavelength is $\lambda_1 = 650 \ nm = 650 *10^{-9} \ m$

The second wavelength is $\lambda_2 = 429 \ m = 420 *10^{-9 } \ m$

The order of the fringe is $n = 2$

The grating is $N = 5000 \ slits / cm$

Generally the slit width is mathematically represented as

$d = \frac{1}{N }$

=> $d = \frac{1}{ 5000 }$

=> $d = 0.0002 \ c m = 2.0 *10^{-6} \ m$

Generally the condition for constructive interference for the first ray is mathematically represented as

$d sin(\theta_1) = n * \lambda_1$

=> $\theta_1 = sin^{-1} [\frac{ 2 * \lambda }{d}]$

=> $\theta_1 = sin^{-1} [\frac{ 2 * 650 *10^{-9} }{ 2*10^{-6}}]$

=> $\theta_1 = 40.5 ^o$

Generally the condition for constructive interference for the second ray is mathematically represented as

$d sin(\theta_2) = n * \lambda_2$

=> $\theta_2 = sin^{-1} [\frac{ 2 * \lambda_1 }{d}]$

=> $\theta_2 = sin^{-1} [\frac{ 2 * 420 *10^{-9} }{ 2*10^{-6}}]$

=> $\theta_2 = 24.8 ^o$

Generally the angular separation is mathematically represented as

$\theta = \theta_1 - \theta_1$

=> $\theta = 42.5^o - 24.8^o$

=> $\theta = 15.7^o$

4 0

3 years ago

A pursuit spacecraft from the planet Tatooine is attempting to catch up with a Trade Federation cruiser. As measured by an obser

madam [21]

Answer:

the speed of the cruiser relative to the pursuit ship is 0.3846c

Explanation:

the solution is in the attached Word file

3 0

3 years ago

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The normal force n with arrow, the gravitational force mg with arrow, and the upward component of the applied force do no work o

lord [1]

Answer and Explanation:

Should let force applied throughout horizontal direction become "F", as well as the displacement of that same sled, become "d." This same force's work seems to be "Fd."
Presently, unless the mass would be doubled as well as the force is applied continues to remain the very same, the work used by the force to keep moving the sled by such the distance "d" would then remain the same.

So that the above seems to be the right answer.

4 0

4 years ago

The forces that cause lava to erupt are... forces

Elenna [48]

It is definitely temerature.
Hoped this helped. :)

7 0

3 years ago

Read 2 more answers