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svp [43]
2 years ago
10

A tennis ball is dropped from 1.13 m above the

Physics
1 answer:
Alex73 [517]2 years ago
7 0

Answer:

-4.71 m/s

Explanation:

Given:

y₀ = 1.13 m

y = 0 m

v₀ = 0 m/s

a = -9.8 m/s²

Find: v

v² = v₀² + 2a (y − y₀)

v² = (0 m/s)² + 2(-9.8 m/s²) (0 m − 1.13 m)

v = -4.71 m/s

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A 60 kilogram astronaut weighs 96 newtons on the surface of the moon. calculate the acceleration due to gravity on the moon.
34kurt
Given: Mass m = 60 Kg

           Weight  W = 96 N

Required: Acceleration due to gravity, g = ?

Formula:  W = mg

                g = W/g

                g = 96 Kg.m/s²/60 Kg   (note: this is the derive unit for Newton "N")

                g = 1.6 m/s²

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2 years ago
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The ph balance is maintained by which organ?
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The Kidneys And Lungs.
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A vehicle should never be parked closer to a fire hydrant than:
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A vehicle should never be parked closer to a fire hydrant than: <span>15 feet
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The coefficients of friction between the load and the flatbed trailershown are μs = 0.40 and μk = 0.30. Knowing that the speed o
SOVA2 [1]

Answer:

50.97 m

Explanation:

m = Mass of truck

\mu_s = Coefficient of static friction = 0.4

v = Final velocity = 0

u = Initial velocity = 72 km/h = \dfrac{72}{3.6}=20\ \text{m/s}

s = Displacement

Force applied

F=ma

Frictional force

f=\mu_s mg

Now these forces act opposite to each other so are equal. This is valid for the case when the load does not slide

ma=\mu_s mg\\\Rightarrow a=\mu_s g\\\Rightarrow a=0.4\times 9.81\\\Rightarrow a=3.924\ \text{m/s}^2

Since the obect will be decelerating the acceleration will be -3.924\ \text{m/s}^2

From the kinematic equations we have

v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0^2-20^2}{2\times -3.924}\\\Rightarrow s=50.97\ \text{m}

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5 0
2 years ago
Sketch a free body diagram for a hot air balloon which is rising off the ground. Indicate the magnitude of the force by utilizin
vaieri [72.5K]

Answer:

   F_net = B -W

The forces of action and reaction are the weight of the balloon that is the force of attraction of the Earth and the outside so the balloon pulls the earth that has an upward direction and is applied to the planet

Explanation:

A hot air balloon is subjected to the force of its weight directed towards the center of the Earth. The thrust due to the cold air released, this thrust is directed upwards.

If we assume that the balloon rises at a constant speed

         F_net = B -W

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The forces of action and reaction are the weight of the balloon that is the force of attraction of the Earth and the outside so the balloon pulls the earth that has an upward direction and is applied to the planet

3 0
2 years ago
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