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3 years ago

A tennis ball is dropped from 1.13 m above the

Physics

1 answer:

Alex73 [517]3 years ago

7 0

Answer:

-4.71 m/s

Explanation:

Given:

y₀ = 1.13 m

y = 0 m

v₀ = 0 m/s

a = -9.8 m/s²

Find: v

v² = v₀² + 2a (y − y₀)

v² = (0 m/s)² + 2(-9.8 m/s²) (0 m − 1.13 m)

v = -4.71 m/s

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$\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}$

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$\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}$

$\small\bm{The \: angle \: between \: the \: vector \: }$

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