Answer:
Step-by-step explanation:
For any quadrilateral to be a parallelogram
i) either both the pairs of opposite sides must be equal
ii) Both the pairs of opposite sides must be parallel
iii) Opposite pairs of angles must be equal
iv) Diagonals must bisect each other.
v) A pair of opposite sides must be parallel and equal
Here we are already given that AB || CD
So either we should be given that AD || BC
or we must be given that AB = CD
Here it is given AB = CD as an option.
So Option A) or the first option is the right answer that AB ≅CD is needed to prove ABCD is a parallelogram.
Answer:
A. 109
Step-by-step explanation:
We know that since AB = CB, then ΔABC is isosceles.
Since AC, one of the sides of ΔABC, is on the diameter of circle D, by definition, we know that ΔABC is also a right triangle. Thus, if ΔABC is an isosceles right triangle, then ∠BAC = ∠BCA = 45°.
Draw a line connecting D to B so that we now have isosceles triangle BDC. Since arc BC is 52°, by definition of central angles, ∠BDC is also equal to 52°. Then, ∠DBC = ∠DCB = (180 - 52)/2 = 64°.
∠BCE = ∠DCB + ∠BCA
∠BCE = 64 + 45 = 109°
The answer is thus A.
<em>~ an aesthetics lover</em>
Area=LengthxWidth so 3/5=7/8xWidth. To get width by itself you must divide both sides by 7/8. When dividing fractions you can flip the fraction and multiply so multiply (3/5)(8/7). To do this just multiply the numerators and denominators to get 24/35 so width = 24/35
<span>The table and plot show the total number of cars parked in a parking lot, 18, after it was open for 3 hours.
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