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Vaselesa [24]
3 years ago
11

How to find a sector of an arc?

Mathematics
1 answer:
Finger [1]3 years ago
6 0

Answer:

easy!

Step-by-step explanation:

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Alex wrote the expanded form for the number 165.038 as "100 60 5 30 8." was he correct? if not, give the correct expanded form.
grin007 [14]

The expanded form for the number 165.038 is 100+60+5+0.03+0.008.

<h3>What is the expended form of decimal numbers?</h3>

Writing decimals in expanded form simply means writing each number according to its place value. This is done by multiplying each digit by its place value and adding them together. Let's look at an example: 2.435. In words, we would say this as two and four hundred thirty-five thousandths.

In the given question expended form 100+60+5+30+8 is wrong.

After decimal point the first digit is at the tenth place and second digit at the hundredth place and third is at the thousandth place and so on....

165.038  = 100+60+5+\frac{0}{10}+\frac{3}{100}+\frac{8}{1000}            

              = 100+60+5+0.03+0.008

Hence, The correct expended form of the given number is 100+60+5+0.03+0.008.

To learn more about expended form from the given link:

brainly.com/question/603715

#SPJ4

5 0
1 year ago
An item Brophy Burger costs n dollars. If the price of the Brophy Burger increases by 30%, the new price can be represented by t
Alika [10]
1.3n (it can be simplified like any other equation just add like terms and remember there is a one before every variable)
5 0
2 years ago
39-50 find the limit.<br> 41. <img src="https://tex.z-dn.net/?f=%5Clim%20_%7Bt%20%5Crightarrow%200%7D%20%5Cfrac%7B%5Ctan%206%20t
Katyanochek1 [597]

Write tan in terms of sin and cos.

\displaystyle \lim_{t\to0}\frac{\tan(6t)}{\sin(2t)} = \lim_{t\to0}\frac{\sin(6t)}{\sin(2t)\cos(6t)}

Recall that

\displaystyle \lim_{x\to0}\frac{\sin(x)}x = 1

Rewrite and expand the given limand as the product

\displaystyle \lim_{t\to0}\frac{\sin(6t)}{\sin(2t)\cos(6t)} = \lim_{t\to0} \frac{\sin(6t)}{6t} \times \frac{2t}{\sin(2t)} \times \frac{6t}{2t\cos(6t)} \\\\ = \left(\lim_{t\to0} \frac{\sin(6t)}{6t}\right) \times \left(\lim_{t\to0}\frac{2t}{\sin(2t)}\right) \times \left(\lim_{t\to0}\frac{3}{\cos(6t)}\right)

Then using the known limit above, it follows that

\displaystyle \left(\lim_{t\to0} \frac{\sin(6t)}{6t}\right) \times \left(\lim_{t\to0}\frac{2t}{\sin(2t)}\right) \times \left(\lim_{t\to0}\frac{3}{\cos(6t)}\right) = 1 \times 1 \times \frac3{\cos(0)} = \boxed{3}

4 0
1 year ago
Find the sine r 13 12 5
Neporo4naja [7]

Answer:

9

Step-by-step explanation:

4 0
3 years ago
(2,8) &amp; (4,60) which one is proportional
tensa zangetsu [6.8K]
They are both proportional. 1:4 and 1:15
4 0
3 years ago
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