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goblinko [34]
3 years ago
6

Ionic compounds are generally crystalline solids with high melting points. water (h2o) is _________________ at room temperature

and both carbon dioxide (co2) and nitrous oxide (n2o) are ____________ at room temperature.
Chemistry
1 answer:
Bumek [7]3 years ago
8 0
Water is a liquid
carbon is a solid
nitrous is a gas
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If I have 6 moles of a gas at a pressure of 3.4 atm and a volume of 10 liters, what
ch4aika [34]

Answer:

The temperature is 69.05 K.  

Explanation:

We have,

Number of moles are 6

Pressure is 3.4 atm and a volume of 10 liters.

It is required to find the temperature. It can be calculated using gas law equation. It says that,

PV=nRT

P is pressure

V is volume

n is number of moles

R is gas constant, R=0.082057\ L-atm/mol-K

T is temperature                

Plugging all the values we get :

T=\dfrac{PV}{nR}\\\\T=\dfrac{3.4\times 10}{6\times 0.082057}\\\\T=69.05\ K

So, the temperature is 69.05 K.  

8 0
3 years ago
Label the figure below with the names of a volcano's parts.
nexus9112 [7]

Answer:

Hello the answer for the volcanos is here below:

7. Pipe

8. Crater

9. Vent

10. lava flow

11. magma chamber

Hope this helps :)

4 0
2 years ago
Help please please help please
Anni [7]

Answer:

I don't fully understand what this is about...

Explanation:

sorry :(

5 0
3 years ago
Read 2 more answers
What happens to these physical properties as the strength of intermolecular forces increases?Increase or decrease?a) melting poi
docker41 [41]

Boiling Point, Melting Point, Viscosity, Surface Tension. Decrease: Vapor Pressure.

6 0
3 years ago
What is the total number of moles (n) of electrons exchanged between the oxidizing agent and the reducing agent in the overall r
Sergeu [11.5K]
Answer:
             5 moles of electrons

Explanation:

The balance equation is as follow,

<span>                   5 Ag</span>⁺ + Mn⁺²<span> + 4 H</span>₂O    →<span>    5 Ag + MnO</span>₄⁻<span> + 8 H</span>⁺

Reduction of Ag:

                         Ag⁺ + 1 e⁻    →    Ag
Or,
                         5 Ag⁺  +  5 e⁻    →    5 Ag

Oxidation of Mn:

                          Mn⁺²   →    MnO₄⁻  +  5 e⁻

Result:
          Hence 5 moles of Ag⁺ accepts 5 electrons from 1 mole of Mn⁺².
4 0
4 years ago
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