Question

What is the total number of moles (n) of electrons exchanged between the oxidizing agent and the reducing agent in the overall redox equation: 5 Ag (aq) +Mn2 (aq) +4H20()5Ag(s)+ MnO4 (aq) +8H' (aq)
a. 1
b. 2
c. 3
d. 5 (
e.?

Answer 1

Answer:
             5 moles of electrons

Explanation:

The balance equation is as follow,

                   5 Ag⁺ + Mn⁺² + 4 H₂O    →    5 Ag + MnO₄⁻ + 8 H⁺

Reduction of Ag:

                         Ag⁺ + 1 e⁻    →    Ag
Or,
                         5 Ag⁺  +  5 e⁻    →    5 Ag

Oxidation of Mn:

                          Mn⁺²   →    MnO₄⁻  +  5 e⁻

Result:
          Hence 5 moles of Ag⁺ accepts 5 electrons from 1 mole of Mn⁺².