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Zanzabum
3 years ago
6

Look at a list of the elements or a periodic table. Identify some pairs of elements that you have heard of that have similar pro

perties. (Will give 5 stars, brainliest, and a thank you.)
Chemistry
1 answer:
nevsk [136]3 years ago
3 0

Two elements have similiar characteristics when they belong to the same family that means that have placed in the same column of the periodic table. So in other words, Helium and Radon are very similar because they are in the same column. Let me know if you need others :)

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B. What do you notice about the number of atoms in one mole?
Doss [256]

Answer:

one mole of atom of any element contains6.022×1033 atoms regardless of the type of elements the mass of one mole of an element depend on what that element is and is equal to atom mass of that element in gram

5 0
3 years ago
I NEED HELP ASAP IF YOU GET IT CORRECT I WILL MARK YOU AS BRAINLIEST
masya89 [10]

Answer:

2 tall 2 short.

Explanation:

If 1 is tall, and 1 is short, 50% would be tall, and the other 50% would be short.

4 0
3 years ago
Read 2 more answers
How many atoms of both elements are there in this molecule: 3N205; O 3 Nitrogen and 15 Oxygen 6 Nitrogen and 5 Oxygen KD 2 Nitro
abruzzese [7]

Answer:

Explanation:

oxygen is a 15 and nitrogen science chemistry i'm guessing

6 0
3 years ago
A 35.66g sample of copper is heated using 600j of energy. if the original temperature of the copper is 85C what is its final tem
ira [324]

This problem is providing the mass, energy, initial temperature and specific heat of a sample of copper that is required to calculate the final temperature.

Thus, we recall the general heat equation:

Q=mC(T_f-T_i)\\

Which has to be solved for the final temperature, T_f as follows:

T_f=T_i+\frac{Q}{mC}

Finally, we plug in the numbers to obtain:

T_f=85\°C+\frac{600J}{35.66g*0.38\frac{J}{g\°C} } \\\\T_f=129.3\°C

However, this result is not given in the choices.

Learn more:

  • brainly.com/question/14383794
8 0
2 years ago
A chemist adds of a M zinc nitrate solution to a reaction flask. Calculate the mass in grams of zinc nitrate the chemist has add
weqwewe [10]

corrected question: A chemist adds 135mL of a 0.21M zinc nitrate solution to a reaction flask. Calculate the mass in grams of zinc nitrate the chemist has added to the flask. Round your answer to significant digits.

Answer:

5.37g

Explanation:

0.21M means ; 0.21mol/dm³

1dm³=1L , so we can say 0.21mol/L

if 0.21mol of Zinc nitrate is contained in 1L of water

x   will be contained in 135mL of water

x= 0.21*135*10³/1

=0.02835moles

number of moles=  mass/ molar mass

mass= number of moles *molar mas

molar mass of Zn(NO₃)₂=189.36 g/mol

mass= 0.02835 *189.36

mass=5.37g

3 0
3 years ago
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