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Keith_Richards [23]
3 years ago
8

In point estimation a. data from the population is used to estimate the population parameter b. data from the sample is used to

estimate the population parameter c. data from the sample is used to estimate the sample statistic d. the mean of the population equals the mean of the sample
Mathematics
1 answer:
icang [17]3 years ago
4 0

Answer:

Option B) data from the sample is used to estimate the population parameter                  

Step-by-step explanation:

Point estimation:

  • Its is the process of getting a point estimate from a sample that describes a population parameter in the best way.
  • We calculate the unknown population parameter with the help of a sample drawn from the population.
  • It is similar to interval estimation.
  • In interval estimation we obtain an interval in which the population parameter may lie but in point estimation we obtain a single value which is the best approximation of population parameter.

Thus, the correct answer is

Option B) data from the sample is used to estimate the population parameter

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Is 3x+2y=8 a quadratic equation?
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Answer:

No.

Step-by-step explanation:

No, it is a linear equation.  There are no exponents on the x or y variables.

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2 years ago
An egg is dropped from a height of 90 ft. If acceleration due to gravity is –16 ft/s2 and initial velocity is 0 ft/s, approximat
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2.4 s B ( i hope this help)
6 0
3 years ago
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Oliver downloaded 15 apps for her phone that altogether, used 2,806 MB of space. If each app used the same amount of space, abou
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Step-by-step explanation:

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2 years ago
In an arithmetic sequence, t4 + t5 + t6 = 300, and t15 +t16+ t17 = 201. Find t18.
stiks02 [169]
In an arithmetic sequence:
Tn=t₁+(n-1)d

t₄=t₁+(4-1)d=t₁+3d
t₅=t₁+(5-1)d=t₁+4d
t₆=t₁+(6-1)d=t₁+5d

t₄+t₅+t₆=(t₁+3d) +(t₁+4d)+(t₁+5d)=3t₁+12d

Therefore:
3t₁+12d=300    (1)


t₁₅=t₁+(15-1)d=t₁+14d
t₁₆=t₁+(16-1)d=t₁+15d
t₁₇=t₁+(17-1)d=t₁+16d

t₁₅+t₁₆+t₁₇=(t₁+14d)+(t₁+15d)+(t₁+16d)=3t₁+45d

Therefore:
3t₁+45d=201    (2)

With the equations (1) and (2) we make an system of equations:

3t₁+12d=300
3t₁+45d=201

we can solve this system of equations by reduction method.

  3t₁+12d=300
-(3t₁+45d=201)
-----------------------------
       -33d=99      ⇒d=99/-33=-3

3t₁+12d=300
3t₁+12(-3)=300
3t₁-36=300
3t₁=300+36
3t₁=336
t₁=336/3
t₁=112

Threfore:

Tn=112+(n-1)(-3)
Tn=112-3n+3
Tn=115-3n

Now, we calculate T₁₈:

T₁₈=115-3(18)=115-54=61

Answer: T₁₈=61




5 0
3 years ago
Simplify the expressions by combining like terms<br><br> 10r - 5r + 3r - 8r
Yuri [45]

Answer:

0

Step-by-step explanation:

Combine like terms, perform the operations with the coefficients of the variable, then write the variable.

10r - 5r + 3r - 8r

= 5r + 3r - 8r

= 8r - 8r

= 0

7 0
2 years ago
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