ANSWER
(3, 11) and (−3, −7)
EXPLANATION
The given system of equations are:

and

or

We equate the two equations to obtain,

We rewrite in standard quadratic form to obtain,

This simplifies to

We solve for x to obtain,




When


When x=-3,

Therefore the solution for the system is (3, 11) and (−3, −7).
I can't see the whole problem
Answer – Always
A negative number raised to an odd power is always negative. When a negative number is raised to an even power, the pairs of negatives will cancel out; but when it is raised to an odd power, after pairs of the negative sign have canceled each other out, there will still be one minus sign left unpaired, which will not cancel out.
<span>
</span>
Alright, so the sum of two days is going to equal zero.
The variable here is what Jesse got on the first day. Let's call it "x".
x-6=0
x is the first day's score, -6 is the second day's score, and the total score is zero.
Now, add 6 to both sides.
x-6=0
+6 +6
x=6
Jesse's score for the first day was (+)6.
It doesn’t represent a function so your answer is B!!