Answer:
The P-value is between 2.5% and 5% from the t-table.
Step-by-step explanation:
We are given that a random sample of 16 students selected from the student body of a large university had an average age of 25 years and a standard deviation of 2 years.
Let = <u><em>true average age of all the students at the university.</em></u>
So, Null Hypothesis, : 24 years {means that the average age of all the students at the university is less than or equal to 24}
Alternate Hypothesis, : > 24 years {means that the average age of all the students at the university is significantly more than 24}
The test statistics that will be used here is <u>One-sample t-test statistics</u> because we don't know about the population standard deviation;
T.S. = ~
where, = sample average age = 25 years
s = sample standard deviation = 2 years
n = sample of students = 16
So, <u><em>the test statistics</em></u> = ~
= 2
The value of t-test statistics is 2.
<u>Also, the P-value of test-statistics is given by;
</u>
P-value = P( > 2) = 0.034 {from the t-table}
The P-value is between 2.5% and 5% from the t-table.