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lubasha [3.4K]
3 years ago
9

Help now pleaseeee!!!

Mathematics
1 answer:
Sliva [168]3 years ago
5 0

Answer:

Step-by-step explanation:

Whitxh answer are u tryna get?

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Given vectors a=(1,2), b=(2,-1), find 4a-3b
riadik2000 [5.3K]
A=(1,2) and b=(2, - 1) . Find 4a - 3b

1st carry out the scalar multiplication 4a and -3b

4a =[4(1) , 4(2) ] = (4 , 8)

-3b = [-3(2) . -3(-1)] = (-6 , +3)

4a - 3b =  [(4-6) , (8+3)] = (-2 , 11)

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3 years ago
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borishaifa [10]
Yea it’s 0.8 help ya
5 0
3 years ago
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Convert 310 yards into feet.
Anuta_ua [19.1K]

Answer:

930 feet

Step-by-step explanation:

=310yards\\\\=310yards*3\\\\=930feet

<em>Note that to convert the yards into feet we must multiply the value by 3.</em>

8 0
3 years ago
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PLEASE HELP ITS REALLY EASYYYY AND ITS DUE IN AN HOUR
Valentin [98]

Answer:

7/9

Step-by-step explanation:

8/9 + -1/9

Rewriting

8/9 - 1/9

Since the denominators are the same, subtract the numerators

(8-1) /9

7/9

8 0
4 years ago
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We roll two fair 6-sided dice. Each one of the 36 possible outcomes is assumed to be equally likely. (a) Find the probability th
Verizon [17]

Answer:

a) There is a 16.6% probability that doubles were rolled.

b) Given that the roll resulted in a sum of 6 or less, there is a 20% probability that doubles were rolled.

c) There is a 30.55% probability that at least one die is a 1.

Step-by-step explanation:

The probability formula is the number of desired outcomes divided by the number of total outcomes.

(a) Find the probability that doubles were rolled. (i.e. the two outcomes are equal)

There are six desired outcomes: (1,1), (2,2), (3,3), (4,4), (5,5), (6,6)

There are 36 total outcomes. So:

P = \frac{6}{36} = 0.166

There is a 16.6% probability that doubles were rolled.

(b) Given that the roll resulted in a sum of 6 or less, find the conditional probability that doubles were rolled.

The following rolls result in a sum of 5 or less:

(1,1), (1,2), (1,3), (1,4), (1,5), (2,1), (2,2), (2,3), (2,4), (3,1), (3,2), (3,3), (4,1), (4,2), (5,1)

So, there are 15 total outcomes.

3 of them are doubled: (1,1), (2,2), (3,3). So

P = \frac{3}{15} = 0.2

Given that the roll resulted in a sum of 6 or less, there is a 20% probability that doubles were rolled.

(c) Find the probability that at least one die is a 1

The following outcomes have at least one die that is 1:

(1,1), (1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(3,1),(4,1),(5,1),(6,1)

So, there are 11 desired outcomes out of 36.

P = \frac{11}{36} = 0.3055

There is a 30.55% probability that at least one die is a 1.

6 0
4 years ago
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