The intervals are given as follows:
- In range notation: [-282, 20,320].
- In set-builder notation: {x|x ∈ ℝ, -282 <= x <= 20,320}
<h3>What is the range of elements notation for interval?</h3>
The range of elements notation for interval is given by:
[a,b].
In which:
In this problem these values are given by:
a = -282, b = 20,320.
Hence the interval in range notation is given by:
[-282, 20,320].
<h3>How to write the interval in set-builder notation?</h3>
The same interval can be written as follows, using set-builder notation?
{x|x ∈ ℝ, a <= x <= b}
Hence, for the situation described in this problem, the set-builder notation for the values is:
{x|x ∈ ℝ, -282 <= x <= 20,320}
More can be learned about notation of intervals at brainly.com/question/27896097
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Answer:
b. 25%
Step-by-step explanation:
(new - old)/ old * 100%
150 - 120 = 30 ... 30/120 = .25 * 100% = 25%
Answer:
A
Step-by-step explanation:
Think of a value on the unit circle that is double of 165.
330 is that so we can use the double Angle Identity
Alpha is 330
so
Answer:
Step-by-step explanation:
Given the equation j – 16 = 7, If Nolan is using substitution to determine if 23 is a solution to the equation, then Nolan need to make j the subject of the formula from the equation. The following statements must therefore be made by Nolan.
First, Nolan must substitute for the value of j in the equation.
To simplify, Nolan must subtract the value of 7 from both sides to have;
j – 16 - 7= 7 - 7
j – 23 = 0
Then Nolan must add 23 to both sides of the equation to get the value of j as shown;
j – 23 + 23 = 0+23
j = 23
23 is therefore a solution to the equation
