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2 years ago

Energy transfer by convection is usually restricted to what type of substance?

1 answer:

7 0

Convection generally describes warm material rising and cool material sinking. In order to have all that rising and sinking, it pretty much needs to be going on in a liquid or other kind of fluid ... something that flows.

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How to feel peace (>_<)

snow_lady [41]

Answer:

Pray to ur God to give you some peace

Explanation:

and then listen to some peace full music

I only know that

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2 years ago

Read 2 more answers

State what would be observed when the following pairs of reagents are mixed in a test tube.

Mandarinka [93]

Answer:

(i). C6H2COOH and Na2CO3(aq)

observation: Bubbles of a colourless gas (carbon dioxide gas)

(ii) CH3CH2CH2OH and KMnO4 /H

observation: The orange solution turns green.

[This is because oxidation of propanol to propanoic acid occurs]

(iii) CH3CH2OH and CH3COOH + conc. H2SO4

observation: A sweet fruity smell is formed.

[This is because an ester, diethylether is formed]

(iv) CH3CH = CHCH3 and Br2 /H2O

observation: a brown solution is formed.

4 0

2 years ago

For each pair, which has higher potential energy?

Allushta [10]

Answer:

Maybe A)

Explanation:

Can you make me the Brainliest answer ?

7 0

3 years ago

formic acid, hcooh, is a weak acid with a ka equal to 1.8×10–4. what is the ph of a 0.0115 m aqueous formic acid solution?

kvasek [131]

The pH of a 0.0115 m aqueous formic acid solution is mathematically given as

pH=2.8424

This is further explained below.

<h3>What is the ph of a 0.0115 m aqueous formic acid solution?</h3>

Generally, the equation for the chemical equation is mathematically given as

HCOOH H^+ + HCOO

$\quad C-C \alpha \quad C \alpha$

$&k a=\frac{c^2 \alpha^2}{e(1-\alpha)}\\\\&K_a=\frac{c \alpha^2}{1-\alpha_4} \quad|\gg\rangle \alpha\\\\&K_a=c \alpha^2\\\\&\alpha=\sqrt{\frac{k a}{c}}\\\\&\alpha=\sqrt{\frac{1.8 \times 10^{-4}}{0.0115}}\\\\&\alpha=\sqrt{156: 527710^{-4}}\\\\&\alpha=\sqrt{1.565 \times 1 \sigma^2}\\\\&\alpha=1.25 \times 10^{-1}\\\\&\alpha=0.125\\$

$&\left[\mathrm{H}^{+}\right]=\mathrm{C \alpha}\\\\&=0.125 \times 0.0115\\\\&=1.4375 \times 10^{-9}\\\\&P=-\log \left[H^{+}\right]\\\\&=-\log \left[1.4375 \times 10^{-3}\right]\\\\&P H=2.8424$