Answer:
the correct answer is Metallic bonding
Explanation:
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Answer:
λ = 5.68×10⁻⁷ m
Explanation:
Given data:
Energy of photon = 3.50 ×10⁻¹⁹ J
Wavelength of photon = ?
Solution:
E = hc/λ
h = planck's constant = 6.63×10⁻³⁴ Js
c = 3×10⁸ m/s
Now we will put the values in formula.
3.50 ×10⁻¹⁹ J = 6.63×10⁻³⁴ Js × 3×10⁸ m/s/ λ
λ = 6.63×10⁻³⁴ Js × 3×10⁸ m/s / 3.50 ×10⁻¹⁹ J
λ = 19.89×10⁻²⁶ J.m / 3.50 ×10⁻¹⁹ J
λ = 5.68×10⁻⁷ m
Calcium Chloride would have a charge of +2
Hopes this helps :)
<span>Given Data :
P 1=92 torr
P 2=313
T 1=296 k
T 2=318
</span><span>Hvap = 47900 Joules
</span>R=1.99 cal/mole-k <span>
Using </span><span>Clausius-Clapeyron equation :
</span>logP2/P1 = delta H/(2.303*R) * (1/T1-1/T2)
log 313/92=0.53
<span>2.303*R= 2.303*1.99
= 4.5829 cal/mole-k
</span><span>1/T1-1/T2=1/296 - 1/318
</span> = 0.0000233
<span>delta H = 0.53*4.5829/0.000233
</span>delta <span>H </span><span>= 10424.622 cal</span>
