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qaws [65]
3 years ago
9

A piston-cylinder device initially contains water liquid-vapor mixture at the pressure of 700 kPa. The liquid-vapor mixture has

0.1 m3 of liquid water and 0.9 m3 of water vapor. Heat is transferred at constant pressure until the temperature reaches 320 °C. (a) What is the initial temperature of the water
Chemistry
1 answer:
GarryVolchara [31]3 years ago
4 0

Given question is incomplete. The complete question is as follows.

A piston-cylinder device initially contains water liquid-vapor mixture at the pressure of 700 kPa. The liquid-vapor mixture has 0.1 m3 of liquid water and 0.9 m3 of water vapor. Heat is transferred at constant pressure until the temperature reaches 320 °C.

(a) What is the initial temperature of the water.

(b) Determine the total mass of the water.

Explanation:

(a) We are given that initially there are two phase regions present.

       Initial temperature = saturation temperature at 700 Kpa

                                       = 165^{o}C

Hence, the initial temperature of the water is 165^{o}C.

(b)  At 700 Kpa, the saturation pressure will be as follows.

       v_{f} = 1.108 \times 10^{-3} m^{3}/kg

      v_{g} = 0.273 m^{3}/kg

So,    m_{f} = \frac{0.1}{1.108 \times 10^{-3}}

                    = 90.25 kg

        m_{g} = \frac{0.9}{0.273}

                    = 3.3 kg

Therefore, total mass will be calculated as follows.

               90.25 kg + 3.3 kg

            = 93.55 kg

Hence, total mass of the water is 93.55 kg.

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Answer:

              1.68 × 10²³ Molecules

Explanation:

                     As we know that 1 mole of any substance contains exactly 6.022 × 10²³ particles which is also called as Avogadro's Number. So in order to calculate the number of particles (molecules) contained by 0.280 moles of Br₂, we will use following relation,

           Moles  =  Number of Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹

Solving for Number of Molecules,

           Number of Molecules  =  Moles × 6.022 × 10²³ Molecules.mol⁻¹

Putting values,

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           Number of Molecules  = 1.68 × 10²³ Molecules

Hence,

           There are 1.68 × 10²³ Molecules present in 0.280 moles of Br₂.

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