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qaws [65]
3 years ago
9

A piston-cylinder device initially contains water liquid-vapor mixture at the pressure of 700 kPa. The liquid-vapor mixture has

0.1 m3 of liquid water and 0.9 m3 of water vapor. Heat is transferred at constant pressure until the temperature reaches 320 °C. (a) What is the initial temperature of the water
Chemistry
1 answer:
GarryVolchara [31]3 years ago
4 0

Given question is incomplete. The complete question is as follows.

A piston-cylinder device initially contains water liquid-vapor mixture at the pressure of 700 kPa. The liquid-vapor mixture has 0.1 m3 of liquid water and 0.9 m3 of water vapor. Heat is transferred at constant pressure until the temperature reaches 320 °C.

(a) What is the initial temperature of the water.

(b) Determine the total mass of the water.

Explanation:

(a) We are given that initially there are two phase regions present.

       Initial temperature = saturation temperature at 700 Kpa

                                       = 165^{o}C

Hence, the initial temperature of the water is 165^{o}C.

(b)  At 700 Kpa, the saturation pressure will be as follows.

       v_{f} = 1.108 \times 10^{-3} m^{3}/kg

      v_{g} = 0.273 m^{3}/kg

So,    m_{f} = \frac{0.1}{1.108 \times 10^{-3}}

                    = 90.25 kg

        m_{g} = \frac{0.9}{0.273}

                    = 3.3 kg

Therefore, total mass will be calculated as follows.

               90.25 kg + 3.3 kg

            = 93.55 kg

Hence, total mass of the water is 93.55 kg.

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Answer:

the amounts and compositions of the overflow V1 and underflow L1 leaving the stage are 75kg and 125kg respectively.

Explanation:

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<u>Feed Phase:</u>

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therefore  Y_{F} = \frac{2.5}{25}

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<u>Underflow:</u>

underflow = L₁ = (unknown) ???

L₁ = E₁ + B

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i.e N₁ = \frac{mass B}{mass(A+C)}

solution in underflow E₁ = Mass (A+C)

<u>Overflow:</u>

Overflow = V₁ = (unknown) ???

solution in overflow V₁ = Mass (A+C)

This is because, B = 0 in overflow

Solid Balance: (since the solid is inert, then is said to be same in feed & underflow).

solid in feed = solid in underflow = 75

75=  E₁ × N₁

75 =  E₁ × 1.5

E₁ = 50kg

Underflow L₁ = E₁ × B

= 50 + 75

=125kg

The Overall Balance: Feed + Solvent = underflow + overflow

100 + 100 = 125 + V₁

V₁ = 75kg

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