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qaws [65]
3 years ago
9

A piston-cylinder device initially contains water liquid-vapor mixture at the pressure of 700 kPa. The liquid-vapor mixture has

0.1 m3 of liquid water and 0.9 m3 of water vapor. Heat is transferred at constant pressure until the temperature reaches 320 °C. (a) What is the initial temperature of the water
Chemistry
1 answer:
GarryVolchara [31]3 years ago
4 0

Given question is incomplete. The complete question is as follows.

A piston-cylinder device initially contains water liquid-vapor mixture at the pressure of 700 kPa. The liquid-vapor mixture has 0.1 m3 of liquid water and 0.9 m3 of water vapor. Heat is transferred at constant pressure until the temperature reaches 320 °C.

(a) What is the initial temperature of the water.

(b) Determine the total mass of the water.

Explanation:

(a) We are given that initially there are two phase regions present.

       Initial temperature = saturation temperature at 700 Kpa

                                       = 165^{o}C

Hence, the initial temperature of the water is 165^{o}C.

(b)  At 700 Kpa, the saturation pressure will be as follows.

       v_{f} = 1.108 \times 10^{-3} m^{3}/kg

      v_{g} = 0.273 m^{3}/kg

So,    m_{f} = \frac{0.1}{1.108 \times 10^{-3}}

                    = 90.25 kg

        m_{g} = \frac{0.9}{0.273}

                    = 3.3 kg

Therefore, total mass will be calculated as follows.

               90.25 kg + 3.3 kg

            = 93.55 kg

Hence, total mass of the water is 93.55 kg.

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4 0
3 years ago
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Answer:

B) As you move across the row, the number of electrons increases and reactivity also increases.

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3 years ago
The following unbalanced equation illustrates the overall reaction by which the body utilizes glucose to produce energy: C6H12O6
s344n2d4d5 [400]

Answer:

the conversion factor is f= 6  mol of glucose/ mol of CO2

Explanation:

First we need to balance the equation:

C6H12O6(s) + O2(g) → CO2(g) + H2O(l) (unbalanced)

C6H12O6(s) + 6O2(g) → 6CO2(g) + 6H2O(l) (balanced)

the conversion factor that allows to calculate the number of moles of CO2 based on moles of glucose is:

f = stoichiometric coefficient of CO2 in balanced reaction / stoichiometric coefficient of glucose in balanced reaction

f = 6 moles of CO2 / 1 mol of glucose = 6  mol of glucose/ mol of CO2

f = 6 mol of CO2/ mol of glucose

for example, for 2 moles of glucose the number of moles of CO2 produced are

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3 0
3 years ago
If 22.5L of nitrogen at 748 mm Hg are compressed to 725 mm Hg at constant temperature. What is the new volume?2.A gas with a vol
kykrilka [37]

Answer:

a)23.2 L

b)68.3kPa

c)7.5 atm

d)60.5L

e)1.67 atm

Explanation:

From Boyle's law:

P1V1=P2V2

P1= 748mmHg

P2=725mmHg

V1= 22.5L

V2??

V2= P1V1/P2= 748×22.5/725= 23.2 L

b)

V1=4.0L

P1= 205×10^3Pa

V2= 12.0L

P2=???

P2= P1V1/V2= 205×10^3×4/12

P2= 68.3×10^3 Pa or 68.3kPa

c)

P1= 1 atm

V1= 196.0L

P2= ??

V2= 26.0L

P2= P1V1/V2=1×196.0/26.0

P2= 7.5 atm

d)

V1= 40.0L

P1= 12.7×10^3Pa

V2=???

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e)

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V2= 60mL

P2=???

P2= P1V1/V2= 1×100/60

P2= 1.67 atm

4 0
3 years ago
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