The power require to keep the car traveling is 6,666 W.
The power of the engine at the given efficiency is 3,999.6 W.
<h3>What is Instantaneous power?</h3>
This the product of force and velocity of the given object.
The power require to keep the car traveling is calculated as follows;
P = Fv
![P = 300\ N \ \times \ \frac{80 \ kmh^{-1}}{3.6 \ km h^{-1}/m/s} \\\\ P = 300 \ N \times 22.22 \ m/s\\\\ P = 6,666 \ W](https://tex.z-dn.net/?f=P%20%3D%20300%5C%20N%20%5C%20%5Ctimes%20%20%5C%20%5Cfrac%7B80%20%5C%20kmh%5E%7B-1%7D%7D%7B3.6%20%5C%20km%20h%5E%7B-1%7D%2Fm%2Fs%7D%20%5C%5C%5C%5C%0AP%20%3D%20300%20%5C%20N%20%5Ctimes%2022.22%20%5C%20m%2Fs%5C%5C%5C%5C%0AP%20%3D%206%2C666%20%5C%20W)
The power of the engine at the given efficiency is calculated as follows;
![E = \frac{P_{out}}{P _{in}} \times 100\%\\\\ 60\% = \frac{P_{out}}{6,666} \times 100\%\\\\ 0.6 = \frac{P_{out}}{6,666} \\\\ P_{out} = 3,999.6 \ W](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7BP_%7Bout%7D%7D%7BP%20_%7Bin%7D%7D%20%5Ctimes%20100%5C%25%5C%5C%5C%5C%0A60%5C%25%20%3D%20%5Cfrac%7BP_%7Bout%7D%7D%7B6%2C666%7D%20%5Ctimes%20100%5C%25%5C%5C%5C%5C%0A0.6%20%3D%20%5Cfrac%7BP_%7Bout%7D%7D%7B6%2C666%7D%20%5C%5C%5C%5C%0AP_%7Bout%7D%20%3D%203%2C999.6%20%5C%20W)
Learn more about efficiency here: brainly.com/question/15418098
Answer:
-414.96 N
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
![v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-3.85^2}{2\times 0.75}\\\Rightarrow a=-9.88\ m/s^2](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2as%5C%5C%5CRightarrow%20a%3D%5Cfrac%7Bv%5E2-u%5E2%7D%7B2s%7D%5C%5C%5CRightarrow%20a%3D%5Cfrac%7B0%5E2-3.85%5E2%7D%7B2%5Ctimes%200.75%7D%5C%5C%5CRightarrow%20a%3D-9.88%5C%20m%2Fs%5E2)
![F=ma\\\Rightarrow F=42\times -9.88\\\Rightarrow F=-414.96\ N](https://tex.z-dn.net/?f=F%3Dma%5C%5C%5CRightarrow%20F%3D42%5Ctimes%20-9.88%5C%5C%5CRightarrow%20F%3D-414.96%5C%20N)
The force the ground exerts on the parachutist is -414.96 N
If the distance is shorter than 0.75 m then the acceleration will increase causing the force to increase
it includes an objects speed and direction
Answer:
the peak wavelength when the temperature is 3200 K = ![9.05625*10^{-7} \ m](https://tex.z-dn.net/?f=9.05625%2A10%5E%7B-7%7D%20%5C%20m)
Explanation:
Given that:
the temperature = 3200 K
By applying Wien's displacement law ,we have
T = 0.2898×10⁻² m.K
The peak wavelength of the emitted radiation at this temperature is given by
= ![\frac{0.2898*10^{-2} m.K}{3200 K}](https://tex.z-dn.net/?f=%5Cfrac%7B0.2898%2A10%5E%7B-2%7D%20m.K%7D%7B3200%20K%7D)
= ![9.05625*10^{-7} \ m](https://tex.z-dn.net/?f=9.05625%2A10%5E%7B-7%7D%20%5C%20m)
Hence, the peak wavelength when the temperature is 3200 K = ![9.05625*10^{-7} \ m](https://tex.z-dn.net/?f=9.05625%2A10%5E%7B-7%7D%20%5C%20m)
Answer:
Explanation:
The cross product of two vectors is given by
![\overrightarrow{A}\times \overrightarrow{B}=\left | \overrightarrow{A} \right |\left | \overrightarrow{B} \right |Sin\theta \widehat{n}](https://tex.z-dn.net/?f=%5Coverrightarrow%7BA%7D%5Ctimes%20%5Coverrightarrow%7BB%7D%3D%5Cleft%20%7C%20%5Coverrightarrow%7BA%7D%20%5Cright%20%7C%5Cleft%20%7C%20%5Coverrightarrow%7BB%7D%20%5Cright%20%7CSin%5Ctheta%20%5Cwidehat%7Bn%7D)
Where, θ be the angle between the two vectors and \widehat{n} be the unit vector along the direction of cross product of two vectors.
Here, K x i = - j
As K is the unit vector along Z axis, i is the unit vector along X axis and j be the unit vector along axis.
The direction of cross product of two vectors is given by the right hand palm rule.
So, k x i = j
j x i = - k
- j x k = - i
i x i = 0