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Vika [28.1K]
4 years ago
12

A fireman is sliding down a fire pole. As he speeds up, he tightens his grip on the pole, thus increasing the vertical frictiona

l force that the pole exerts on the fireman. When the force on his hands equals his weight, what happens to the fireman?
A. The fireman comes to a stop.
B. The fireman descends with slower and slower speed.
C. The fireman descends with a smaller but non-zero acceleration.
D. The fireman continues to descend, but with constant speed.
E. The acceleration of the fireman is now upward.
Physics
1 answer:
Gnesinka [82]4 years ago
6 0

Answer:

The fireman continues to descend but with constant speed.

Explanation:  

According to Newton first law of motion, The object which is rest continues to remain at rest or object moving with constant speed move with constant velocity when acted upon by an unbalanced force.

When the net force acting on the object becomes zero the object moves with constant speed.

Hence when the frictional force acting on the fireman hands equals to his body weight , the net force acting on the fireman becomes zero and thus fireman continues to descend with constant speed.

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What is the acceleration of an object that starts at rest and reaches 100 m/s in 4 seconds
azamat

Answer:

<h3>The answer is 25 m/s²</h3>

Explanation:

The acceleration of an object given it's velocity and time taken can be found by using the formula

a =  \frac{v}{t}

where

v is the velocity

t is the time

From the question

v = 100 m/s

t = 4 s

We have

a =  \frac{100}{4}  \\

We have the final answer as

<h3>25 m/s²</h3>

Hope this helps you

7 0
4 years ago
The stoplight had just changed and a 2100 kg Cadillac had entered the intersection, heading north at 3.2 m/s , when it was struc
elena55 [62]

Explanation:

It is given that,

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Speed of Cadillac, v_1=3.2\ m/s (towards north)

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The cars stuck together and slid to a halt, leaving skid marks angled 35 degrees north of east.

According to the law of conservation of momentum,

The momentum along x axis, m_1v_1=(m_1+m_2)\ usin35............(1)

The momentum along y axis, m_2v_2=(m_1+m_2)\ ucos35...........(2)

From equation (1) and (2) it is clear that,

\dfrac{m_1v_1}{m_2v_2}=tan35

v_2=\dfrac{m_1v_1}{m_2\ tan35}

v_2=\dfrac{2100\times 3.2}{1100\times \ tan35}

v_2=8.72\ m/s

So, the Volkswagen going just before the impact is 8.72 m/s. Hence, this is the required solution.

6 0
3 years ago
A kid on a playground swing makes 6 complete to-and-fro swings each 30 seconds
Evgesh-ka [11]
I assume that you want to find out what's the frequency is.

Number of oscillation = 6  which being done in 30 second.

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Hope this help
4 0
3 years ago
A parallel circuit has two 8.0-ohm resistors and a power source of 9.0 volts. If a 12.5-ohm resistor is added to the circuit in
Airida [17]
-- The two 8-ohm resistors in parallel are equivalent to
a single 4-ohm resistor.

-- The current in the circuit is 

                 (voltage) / (resistance) = (9v) / (4ohms) = 2.25 Amperes

-- If another resistor is added in parallel, then no matter how large
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(When another lane is added to a road, the traffic capacity of the
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The circuit is now equivalent to a 12.5-ohm resistor in parallel
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-- The new current is  (9v) / (3.03 ohms)  =  2.97 Amperes
            
7 0
3 years ago
A bowling ball rolls 33\,\text m33m33, start text, m, end text with an average speed of 2.5\,\dfrac{\text m}{\text s}2.5 s m ​ 2
asambeis [7]

The ball rolled for 13.2 s

<h3>Further explanation</h3>

Speed is scalar and no direction

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A bowling ball rolls 33 m, with average speed = 2.5 m/s

So elapsed time :

\tt t=\dfrac{33~m}{2.5`m/s}=13.2~s

4 0
3 years ago
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