Each orbit is limited to a maximum of four electrons true or false

Calvert likes to paddle around in his canoe. One day it sprung a leak and started to fill with water. Luckily, Calvert was able

kari74 [83]

When the canoe leaked, the boat sank because it has a leak. The boat must have a strong base at its bottom to enable itself to float. If this is damaged, the water can now enter due to the hole thereby increasing the velocity of water coming in.

7 0

3 years ago

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A 1-kilogram mass is attached to a spring whose constant is 14 N/m, and the entire system is then submerged in a liquid that imp

ch4aika [34]

Answer:

Part(a): The equation of motion is $\bf{x(t) = \dfrac{7}{5}~e^{-2t} - \dfrac{2}{5}~e^{-7t}}$ .

Part(b): The equation of motion is $\bf{x(t) = -e^{-2t} + \dfrac{11}{5}~e^{-7t}}$ .

Explanation:

If ' $m$ ' be the mass of the object, ' $k$ ' be the force constant and ' $\beta$ ' be the damping constant, then the equation of motion of the particle can be written as

$\dfrac{d^{2}x}{dt^{2}} + \dfrac{\beta}{m} \dfrac{dx}{dt} + \dfrac{k}{m}x= 0.........................................(I)$

Given $m$ = 1 Kg, $k$ = 14 $N~m^{-1}$ , $\beta$ = 9. Substituting these values in equation (I),

$\dfrac{d^{2}x}{dt^{2}} + 9~\dfrac{dx}{dt} + 14~x= 0$

Taking a trial solution $x(t) = e^{mt}$ , the auxiliary equation can be written as

$m^{2} + 9m + 14 = 0............................................................(II)$

and its solutions are $m_{1} = -2~and~m_{2} = -7$ , resulting the general solution

$x(t) = C_{1}~e^{-2t} + C_{2}~e^{-7t}....................................................................(III)$

The velocity at any instant of time of the mass is

$v(t) = -2C_{1}~e^{-2t} _7~C_{2}~e^{-7t}..............................................................(IV)$

Part(a):

Given $x(t=0) = 1 m,~and~v(t=0) = 0~m~s^{-1}$ . Substituting these values in equation (III) and (IV),

$&& 1 = C_{1} + C_{2}......................(V)\\&and,& 0 = -2C_{1} - 7C_{2}.......................(VI)$

Solving equations (V) and (VI), we have

$C_{1} = \dfrac{7}{5}~and~C_{2} = \dfrac{-2}{5}$

So the equation of motion is

$x(t) = \dfrac{7}{5}~e^{-2t} - \dfrac{2}{5}~e^{-7t}$

Part(b):

Given $x(t=0) = 1 m,~and~v(t=0) = - 12~m~s^{-1}$ . Substituting these values in equation (III) and (IV),

$&& 1 = C_{1} + C_{2}......................(VII)\\&and,& -12 = -2C_{1} -7C_{2}.......................(VIII)$

Solving equations (V) and (VI), we have

$C_{1} = -1~and~C_{2} = \dfrac{11}{5}$

So the equation of motion is

$x(t) = -e^{-2t} + \dfrac{11}{5}~e^{-7t}$

3 0

3 years ago

Eugene is studying the levels of structural organization of an animal’s body. Which level would describe a dog’s eye

mrs_skeptik [129]

The levels of structural organization:
cell ---> tissue ---> organ ---> organ system ---> organism

A dog's eye would be an organ.

6 0

3 years ago

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What is the gravitational force between two bowling balls with 7kg mass each and 1.1m apart ?

Rufina [12.5K]

Answer:

2.7010 * 10^-9 N

Explanation:

solution;

mass (m1) = 7kg

mass (m2) = 7kg

distance(d) = 1.1m

universal gravitational constant (G) = 6.67 * 10^-11

we know that,

gravitational force = (G*m1*m2)/d^2

= ((6.67 * 10^-11) *7 *7)/(1.1)^2

=(3.2683 *10^-9)/1.21

= 2.7010 * 10^-9

Gravitational force = 2.7010 * 10^-9 N

8 0

2 years ago

What is the definition of force According to netwon's first law of motion

defon

Answer:

Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. ... In other words, if object A exerts a force on object B, then object B also exerts an equal force on object A.

6 0

2 years ago

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