Answer:
Explanation:
The speed of hare = .15 x 25 = 3.75 m /s . Let tortoise took t second to complete the race .
Distance traveled by it = .15 t
Distance traveled by hare = .15 t - .35 m
Time taken by hare to complete this distance
= t - 5 x 60 s
Speed of hare
= Distance / time
( .15t-.35 ) / t - 300 , so
t = 312.40
= 5 minutes 12.4 seconds
Distance of race
312.4 x speed of tortoise
= 312.4 x .15
= 46.85 m
Explanation:
(a). First of all, we calculate the number of atoms per cm^{3}, and by taking into account that each atom contributes with one free electron we have
(b)
(c)
I hope this is useful for you
P.D please change 1.628 (the diameter) by 0.814(the radius) in the calculation
:)
Because the two paths are perpendicular, therefore the
target proton's new path must be at 30 degrees from the original
direction.
Using the law of conservation of momentum about the original direction:
m (400 m/s) = m (v1) cos(60) + m (v2) cos(30)
Cancelling m since the two protons have similar mass.
(v1)cos(60) + (v2)cos(30) = 500 m/s ---> 1
Now by using the law conservation of momentum perpendicular to the original
direction:
m (0 m/s) = m (v1) sin(60) – m (v2) sin(30)
Which simplifies to:
(v1)sin(60) - (v2)sin(30) = 0 m/s
v2 = v1 * sin(60) / sin(30) = v1 * sqrt(3) ---> 2
Plugging equation 2 to equation 1:
(v1) (1/2) + (v1 * sqrt(3)) sqrt(3)/2 = 500 m/s
(1/2) (v1) + (3/2) (v1) = 500 m/s
2 (v1) = 500 m/s
v1 = 250 m/s
Thus, from equation 2:
v2 = v1*sqrt(3) = (250 m/s) sqrt(3) = 433.01 m/s
So,
A. The target proton's speed is about 433 m/s
B. The projectile proton's speed is 250 m/s
Answer:
0.6375 cm
Explanation:
coefficient of linear expansion of copper, α =
Lo = 25 m
Δ T = 25 degree C
According to the formula of thermal expansion which is linear in nature is given by
Where, ΔL be the change in length
=0.6375 cm
The answer should be Reification but I don’t see an option for that one