1. lifts it chest high
The force opposing to this action is the force due to
gravity. Therefore the work done is:
W1 = m g d
where m is mass of the barbell, g is gravity and d is displacement
2. holds it for 30 seconds
Work is a product of force and displacement, since there
is no displacement, therefore work done is zero.
W2 = 0
3. puts it down slowly
If the barbell was dropped, then it would simply be a free
fall. But since it was not, so the work done here is also equal to the weight
of the barbell times displacement:
W3 = m g d
We can see that W1 = W3, and since W2 = 0, therefore the answer
is:
<span>w3 = w1 > w2</span>
Answer:
4.16 L
Explanation:
Assuming constant temperature,
At the edge of Typhoon Odessa: P₁ = 1 atm = 1013.3 mbar,
V₁ = 4.0 L
At the center of Typhoon Odessa: P₂ = (1013.3 - 40.0) mbar = 973.3 mbar
V₂ = ? L
For a fixed amount of gas at constant temperature (Boyle's law) : P₁V₁ = P₂V₂
V₂ = V₁ × (P₁/P₂)
V₂= (4.0) × (1013.3/973.3)
V₂= 4.16 L
Answer:
The acceleration of the box is 3 m/s²
Explanation:
Given;
mass of the box, m = 12 kg
horizontal force pulling the box forward, Fx = 48 N
frictional force acting against the box in opposite direction, Fk = 12 N
The net horizontal force on the box, F = 48 N - 12 N
The net horizontal force on the box, F = 36 N
Apply Newton's second law of motion to determine the acceleration of the box;
F = ma
where;
F is the net horizontal force on the box
a is the acceleration of the box
a = F / m
a = 36 / 12
a = 3 m/s²
Therefore, the acceleration of the box is 3 m/s²
In order to calculate the thermal energy, first let's calculate the power, using the formula:
For a voltage V = 9 Volts and a resistance R = 50 ohms, we have:
Now, multiplying the power by the time (in seconds), we can find the energy:
In scientific notation, we have an energy of 7.3 * 10^2 J, therefore the correct option is the fourth one.
Answer:A powder is an assembly of dry particles dispersed in air. If two different powders are mixed perfectly, theoretically, three types of powder.
Explanation:
