Given:
The milk cost in year 2000 = $2.79
In 2015, the cost of milk = $3.98
To find:
The % portion.
Solution:
We have to find the % portion. It means, we need to find the change percent.
![\%\text{Change}=\dfrac{\text{New value - Initial value}}{\text{Initial value}}\times 100](https://tex.z-dn.net/?f=%5C%25%5Ctext%7BChange%7D%3D%5Cdfrac%7B%5Ctext%7BNew%20value%20-%20Initial%20value%7D%7D%7B%5Ctext%7BInitial%20value%7D%7D%5Ctimes%20100)
![\%\text{Change}=\dfrac{3.98-2.79}{2.79}\times 100](https://tex.z-dn.net/?f=%5C%25%5Ctext%7BChange%7D%3D%5Cdfrac%7B3.98-2.79%7D%7B2.79%7D%5Ctimes%20100)
![\%\text{Change}=\dfrac{1.19}{2.79}\times 100](https://tex.z-dn.net/?f=%5C%25%5Ctext%7BChange%7D%3D%5Cdfrac%7B1.19%7D%7B2.79%7D%5Ctimes%20100)
![\%\text{Change}=0.4265233\times 100](https://tex.z-dn.net/?f=%5C%25%5Ctext%7BChange%7D%3D0.4265233%5Ctimes%20100)
![\%\text{Change}=42.65233\%](https://tex.z-dn.net/?f=%5C%25%5Ctext%7BChange%7D%3D42.65233%5C%25)
![\%\text{Change}\approx 42.65\%](https://tex.z-dn.net/?f=%5C%25%5Ctext%7BChange%7D%5Capprox%2042.65%5C%25)
Therefore, the % portion is 42.65%.
I’m pretty sure it’s c if not sorry
Well, the sum has to be less than 83. Do you think maybe it could be 82 ? ?
Sadly, it couldn't be 82. If two integers are consecutive, then one is even and
one is odd, and their sum is always odd. So the greatest sum less than 83
is going to be 81 .
Since the integers are consecutive, both of them have to be right around
half of 81 . Half of 81 is (40 and 1/2), so let's try 40 and 41 :
<em>40 + 41 = 81 </em> That's it ! yay!
Grade 8: 8 + 2 + 12 + 3 + 5 = 30 students
Grade 9: 6 + 3 + 10 + 2 + 4 = 25 students
8th graders who prefer football: 12
Percentage: 12/30 * 100 = 40%
Answer: 40%
8th graders who prefer baseball: 2
Percentage: 2/30 * 100% = 6.66%
Answer: 7%
9th graders who prefer soccer: 4
Percentage: 4/25 * 100% = 16%
Answer: 16%
Answer:
A
Step-by-step explanation:
its the only negative whilst others are positive