Answer:
Hello! so this is what I was able to find related to your question.
Explanation:
The oxidation number of this molecule, called a bromate molecule, is -1. It should be correctly written BrO3-. It has this net charge of negative 1 because the bromine has an oxidation number of +5, while oxygen has it's normal oxidation of -2.
Answer: Thus the mass, in grams, of 27 moles of smooth muscle myosin is 12960000 grams
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass, occupies 22.4 L at STP contains avogadro's number 
of particles.
Molecular mass of protein = 480,000 g/mol
Thus 1 mole of protein weighs = 480,000 g
So 27 moles of protein weighs = 
Thus the mass, in grams, of 27 moles of smooth muscle myosin is 12960000 grams
Answer:
in position and time graphs the slope of line indicates the velocity
Answer:
1610.7 g is the weigh for 4.64×10²⁴ atoms of Bi
Explanation:
Let's do the required conversions:
1 mol of atoms has 6.02×10²³ atoms
Bi → 1 mol of bismuth weighs 208.98 grams
Let's do the rules of three:
6.02×10²³ atoms are the amount of 1 mol of Bi
4.64×10²⁴ atoms are contained in (4.64×10²⁴ . 1) /6.02×10²³ = 7.71 moles
1 mol of Bi weighs 208.98 g
7.71 moles of Bi must weigh (7.71 . 208.98 ) /1 = 1610.7 g
