E^2x -2e^x -8=0 => e<span>^(2x) -2e^x -8=0
Temporarily replace e^x with y.
Then (y)^2 - 2y - 8 = 0. Factors are (y-4) and (y+2).
Roots are y = 4 and y= -2.
Now remembering that we temporarily replaced e^x with y, we let
y=4 = e^x. We need to solve for x. Taking the natural log of both sides, we get:
ln 4 = x (answer)
We have to discard the other root (y= -2), because we cannot take the ln of a negative number.
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Answer:
-2, 0, 1/2, 1
Step-by-step explanation:
Because they both have two angles tbat are the same size
Answer:
(4,-2)
Step-by-step explanation:
Answer:
1 solution.
General Formulas and Concepts:
<u>Pre-Algebra</u>
Step-by-step explanation:
<u>Step 1: Define equation</u>
9(z + 8) = -9z - 72
<u>Step 2: Solve for </u><em><u>x</u></em>
- Distribute 9: 9x + 72 = -9z - 72
- Add 9z to both sides: 18z + 72 = -72
- Subtract 72 on both sides: 18z = -144
- Divide 18 on both sides: z = -8
Here we see that we will get only 1 solution for <em>z</em>.
