All categories

3 years ago

How do i cross multiply 1/25 = x/125

Mathematics

1 answer:

irakobra [83]3 years ago

4 0

Multiply 1 by 125, and 25 by x so you can solve for x.

You might be interested in

Matteo spends a total of 38 min exercising. He walks for 6 min to warm up and then runs at a constant rate of 8 min per mile for

umka2103 [35]

Answer:

No, he not correct because he only ran 4 mi

Step-by-step explanation:

If he walks for 6 min out of the 38 min, then he ran for 32 min.

d = rt 1 mi = 8r

r = 1/8 = 1 mi/8 min Since he ran 32 min we have

d = 1/8(32) = 4 mi.

No, he not correct because he only ran 4 mi

6 0

3 years ago

Write a function for the thickness of folding a piece of paper that is 0.2 millimeters thick. Let t be the thickness of the fold

kumpel [21]

T(n) = 0.2n

Hope I helped!

Let me know if you need anything else!

~ Zoe

6 0

3 years ago

Let X be the random variable representing the number of calls received in an hour by a 911 emergency service. A portion of the p

ivolga24 [154]

For any distribution, the sum of the probabilities of all possible outcomes must be 1. In this case, we have to have

$P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)=1$

We're told that $p=P(X=1)=P(X=2)$ , and we're given other probabilities, so we have

$0.25+2p+0.10+0.05=1\implies2p=0.6\implies p=0.3$

The expected number of calls would be

$E[X]=\displaystyle\sum_xx\,P(X=x)$

$E[X]=0\,P(X=0)+1\,P(X=1)+\cdots+4\,P(X=4)$

$E[X]=1.4$

6 0

2 years ago

7.3-11 + 10 - (5 x 23)<br> simplify

musickatia [10]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Parallelogram ABCD has vertex coordinates a(0,2) b (6,2) c (8,6 and d (2,6) write a rule to find the vertex coordinates of a par

Anastasy [175]

Answer: The rule is explained.

Step-by-step explanation: As shown in the attached figure, ABCD is a parallelogram with vertices A(0,2), B(6,2), C(8,6) and D(2,6).

Suppose, we are to find the vertices of a parallelogram PQRS that is smaller than but similar to ABCD, then we can follow the following rule.

Let us consider a positive real number k. Then the new coordinates of smaller and similar parallelogram PQRS will be

Co-ordinates of P will be (k,2+k),

Co-ordinates of Q will be (6-k,2+k),

Co-ordinates of R will be (8-k,6-k)

and

co-ordinates of S will be (2+k,6-k).

Taking any positive real value of k, we will get a new, smaller parallelogram which will be similar to ABCD.

8 0

3 years ago