Answer:
m∠1= m∠5= 100°, m∠2= m∠6= 80°, m∠4=m∠8= 155°, m∠3= m∠7= 25°
Step-by-step explanation:
Supposing ∠1,∠2 make up a straight angle.Let ∠1, ∠5 and ∠2 and ∠6 be corresponding angles on a transversal drawn on two parallel lines. ∠3,∠4 and∠5 ∠6 be interior angles
If m ∠= 80° them m∠ 1= 100°
As ∠1= 4. m∠3 therefore
100°= 4.m∠3
m∠3= 100/4= 25°
Again supposing m∠3+ m∠4= 180°
m∠4= 180°- 25°= 155°
m∠4 =m∠8= 155°
m∠8 + m∠7= 180°
m∠7= 180°- 155°= 25°
Let ∠5 and ∠1 be corresponding angles so m∠5= m∠1= 100°
and m∠6= m∠2= 80°
