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Zielflug [23.3K]
3 years ago
14

A basketball player makes 60% of his free throws. We set him on the line of free-throw and informed him to shoot free throws unt

il he misses. Let the random variable X be the number of free throws taken by the player until he misses. Assuming that his shots are independent, find the probability that he will miss the shot on his 6th throw. Show work detail please
a) 0.04666
b) 0.03110
c) 0.01866
d) 0.00614
Mathematics
1 answer:
pshichka [43]3 years ago
7 0

Answer:

B. 0.03110

Step-by-step explanation:

Given

Probability of Hit = 60%

Required

Determine the probability that he misses at 6th throw

Represent Probability of Hit with P

P = 60\%

Convert to decimal

P = 0,6

Next; Determine the Probability of Miss (q)

Opposite probabilities add up to 1;

So,

p + q = 1

q = 1 - p

Substitute 0.6 for p

q = 1 - 0.6

q = 0.4

Next,is to determine the required probability;

Since, he's expected to miss the 6th throw, the probability is:

Probability = p^5 * q

Probability = 0.6^5 * 0.4

Probability = 0.031104

Hence;

<em>Option B answers the question</em>

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Daily high temperatures in St. Louis for the last week were as​ follows: 95​, 92​, 93​, 92​, 95​, 90​, 90 ​(yesterday). ​a) The
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Answer:

a) T = 91.7 degrees

b) T = 90 degrees

c) MAD = 1.9

d) MSE = 5.05

Step-by-step explanation:

Given:

- Daily high temperatures in St. Louis for the last week were as​ follows:

                                   95​, 92​, 93​, 92​, 95​, 90​, 90

Find:

a) Forecast the high temperature today, using a 3-day moving average.

b) Forecast the high temperature today, using a 2-day moving average.

c) Calculate the mean absolute deviation based on a 2-day moving average, covering all days in which you can have a forecast and an actual temperature.

d) The mean squared error for the​ 2-day moving average​

Solution:

a)

- The set of 3 day moving average is as follows:

4.   (95 + 92 + 93) ÷ 3 = 93.33⁰C

5.  (92 + 93 + 92) ÷ 3 = 92.33⁰C

6.  (93 + 92 + 95) ÷ 3 = 93.33⁰C

7.  (92 + 95 + 90) ÷ 3 = 92.33⁰C

8.  (95 + 90 + 90) ÷ 3 = 91.667⁰C

- Now use these points on excel sheet to forecast the temperature for today. The line of best fit is given:

T = 91.7 degrees

b)

- The set of 2 day moving average is as follows:

3.   (95 + 92) ÷ 2 = 93.5⁰C

4.  (95 + 93) ÷ 2 = 92.5⁰C

5.  (93 + 92) ÷ 2 = 92.5⁰C

6.  (92 + 95) ÷ 2 = 93.5⁰C

7.  (95 + 90) ÷ 2 = 92.5⁰C

8. (90 + 90) ÷ 2 = 90⁰C

- Now use these points on excel sheet to forecast the temperature for today. The line of best fit is given:

T = 90 degrees

c)

                             Error             Error^2

3.   93.5⁰C            0.5                  0.25

4.   92.5⁰C            0.5                  0.25

5.   92.5⁰C            2.5                  6.25

6.   93.5⁰C            3.5                  12.25

7.   92.5⁰C            2.5                  6.25

8.   90⁰C

- The mean absolute deviation as follows:

                              MAD = Sum of all errors  / 5

                              MAD = (0.5+0.5+2.5+3.5+2.5)  / 5

                              MAD = 1.9

d)

- The mean squared error deviation as follows:

                              MSE = Sum of all error^2  / 5

                              MSE = (0.25+0.25+6.25+12.25+6.25)  / 5

                              MSE = 5.05

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