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4vir4ik [10]
3 years ago
11

Will mark as BRAINLIEST.....

Physics
1 answer:
tigry1 [53]3 years ago
7 0

Answer:

Explanation:

Initially the packet was ascending up with the balloon.

Taking upward as positive direction;

initial velocity, u = 4.9 m/s

final velocity = v m/s

initial height, h₁ = 100 m  

final height, h₂ = 0

a = -9.8 m/s²

time taken = t seconds

Considering the second equation of motion.

S = ut + 1/2at^2

s = ut + 0.5at²

(h₂-h₁) = ut + 0.5at²

0- 100 = 4.9t + 0.5×(-9.8)×t²

-100 = 4.9t - 4.9t²

4.9t² -4.9t -  100 =0

t² -t - 20.41 = 0

Using : b±√(b²-4ac))/(2a)....  1

Where a =1, b = -1 c =-20.408

Substituting the values into equation 1

Solving it, we get  t = 5.045s

v = u + at = 4.9 -9.8×5.045 = 4.9 - 49.44 = -44.54 m/s

The final velocity is -44.54 m/s, and it took  5.045s to reach the ground.

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In this scenario, if the scientists want the probe to enter the orbit they should ensure that probe moves in direction X. This ultimately implies that, the probe must move in the same direction as the orbit, in order to enter it.

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Answer:

\boxed {\boxed {\sf D. \ 6.02*10^{23} \ atoms}}

Explanation:

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Regardless of the particles, there will always be <u>6.02*10²³</u> (also known as Avogadro's Number) particles in one mole of a substance.

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Consider a container of oxygen gas at a temperature of 23°C that is 1.00 m tall. Compare the gravitational potential energy of a
Sergio039 [100]

Answer:

Yes, it is reasonable to neglect it.

Explanation:

Hello,

In this case, a single molecule of oxygen weights 32 g (diatomic oxygen) thus, the mass of kilograms is (consider Avogadro's number):

m=1molec*\frac{1mol}{6.022x10^{23}molec} *\frac{32g}{1mol}*\frac{1kg}{1000g}=5.31x10^{-26}kg

After that, we compute the potential energy 1.00 m above the reference point:

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Then, we compute the average kinetic energy at the specified temperature:

K=\frac{3}{2}\frac{R}{Na}T

Whereas N_A stands for the Avogadro's number for which we have:

K=\frac{3}{2} \frac{8.314\frac{J}{mol*K}}{6.022x10^{23}/mol}*(23+273)K\\ \\K=6.13x10^{-21}J

In such a way, since the average kinetic energy energy is about 12000 times higher than the potential energy, it turns out reasonable to neglect the potential energy.

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A light ray incident on a block of glass makes an incident angle of 50.0° with the normal to the surface. The refracted ray in t
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Answer:

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