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natta225 [31]
2 years ago
9

Mass m1 on the frictionless table of the figure is connected by a string through a hole in the table to a hanging mass m2

Physics
1 answer:
Setler [38]2 years ago
8 0

For a mass m1 on the frictionless table, the speed m1 must rotate a with radius r if m2 is to remain hanging at rest is mathematically given as

v=\sqrt{m1/m2*xg}

<h3>What speed must m1 rotate in a circle of radius r if m2 is to remain hanging at rest?</h3>

Generally, the equation for the Force  is mathematically given as

Fc=Fw

Therefore

\frac{m1v1}{x}=m2g

v=\sqrt{m1/m2*xg}

In conclusion,  if m2 is to remain hanging at rest the speed of ratio of m1 is calcuylated using

v=\sqrt{m1/m2*xg}

Read more about Speed

brainly.com/question/4931057

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