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2 years ago

Mass m1 on the frictionless table of the figure is connected by a string through a hole in the table to a hanging mass m2

1 answer:

8 0

For a mass m1 on the frictionless table, the speed m1 must rotate a with radius r if m2 is to remain hanging at rest is mathematically given as

$v=\sqrt{m1/m2*xg}$

<h3>What speed must m1 rotate in a circle of radius r if m2 is to remain hanging at rest?</h3>

Generally, the equation for the Force is mathematically given as

Fc=Fw

Therefore

$\frac{m1v1}{x}=m2g$

$v=\sqrt{m1/m2*xg}$

In conclusion, if m2 is to remain hanging at rest the speed of ratio of m1 is calcuylated using

$v=\sqrt{m1/m2*xg}$

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Answer:

Newton's Second Law of Motion

Explanation:

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It can also be expressed as:

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