The available options are:
Mint is a dicot.
Mint is a monocot.
Mint is an angiosperm.
Mint is a bulb plant.
Answer:
Mint is a dicot.
Explanation:
Given the fact that Mint is considered to be a member of Lamiaceae, an angiosperm plant which is characterized by typically having leaves that consist of reticulate vacation and appears like veins in structure. It also has a seed that contains two cotyledons.
Hence, it is considered a DICOT PLANT due to these characteristics. The botanical name of Mint is referred to as Mentha arvensis.
Answer:
A) False
B) False
C) True
D) False
Explanation:
A) False, because when leaving the field, the coil experiences a magnetic force to the right.
B) When the loop is entering the field, the magnetic flux through it will increase. Thus, induced magnetic field will try to decrease the magnetic flux i.e. the induced magnetic field will be opposite to the applied magnetic field. The applied magnetic field is into the plane of figure and thus the induced magnetic field is out of the plane of figure. Due to that reason, the current would be counterclockwise. So the statement is false.
C) When the loop is leaving the field, the magnetic flux through the loop will decrease. Thus, induced magnetic field will try to increase the magnetic flux i.e. the inducued magnetic field will be in the same direction as the applied magnetic field. The applied magnetic field is into the plane of figure and thus the induced magnetic field is also into the plane of figure. Due to that reason, the current would be clockwise. So the statement is true.
D) False because when entering the field magnetic force will be toward left side
Answer:
1. 18.25 m/s
2. 0 m/s
Explanation:
1.So the centripetal acceleration of the ball at this lowest point must be, taking gravity into account
The speed at this point would then be
2. Similarly, if T = mg, then the centripetal acceleration must be
As the ball has no centripetal acceleration, its speed must also be 0 as well.
Answer:
<em>2.72 x 10^-43 m</em>
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Explanation:
mass of the telescope = 7500 kg
speed of the telescope = 3.25 x 10^5 m/s
de Broglie's wavelength of the telescope is given as
λ = h/mv
where
λ is the wavelength of the telescope
h is the plank's constant = 6.63 × 10-34 m^2 kg/s
m is the mass of the telescope = 7500 kg
v is speed of the telescope = 3.25 x 10^5 m/s
substituting value, we have
λ = (6.63 × 10-34)/(7500 x 3.25 x 10^5)
λ = <em>2.72 x 10^-43 m</em>
Answer:
C. It is the result of diffraction
Explanation:
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