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Kamila [148]
2 years ago
12

~~~~~NEED HELP ASAP~~~~~

Physics
1 answer:
Romashka-Z-Leto [24]2 years ago
8 0

Answer:

Centripetal Acceleration 18.75 m/s^2, Rotational Kinetic Energy 843.75 J

Explanation:

a Linear acceleration (we cant find tangential acceleration with the givens so we will find centripetal)

a= ω^2*r

ω= 300rev/min

convert into rev/s

300/60= 5rev/s

a= 18.75m/s^2

b) use Krot= 1/2 Iω^2

plug in gives

1/2(30*2.25)(25)= 843.75 J

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The apparent height of a building 10.5 km away is 0.02 radians. What is the approximate height of the building to the nearest me
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Answer:

Approximate height of the building is 23213 meters.

Explanation:

Let the height of the building be represented by h.

0.02 radians = 0.02 × \frac{180^{o} }{\pi }

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Applying the trigonometric function, we have;

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So that,

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⇒ h = Tan 1.146° x 10500

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The approximate height of the building is 23213 m.

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