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Gwar [14]
3 years ago
12

I

Mathematics
1 answer:
iren2701 [21]3 years ago
6 0

Answer:

The distance between points A and B is 13

Step-by-step explanation:

We need to find distance between points A and B

Looking at the graph,

Point A : (2,6) and Point B: (-3,-6)

We need to find the distance between these points.

The formula used is: Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\

We have Points A : (2,6) and  B: (-3,-6)

So, x_1=2, y_1=6, x_2=-3, y_2=-6

Putting values in formula and finding distance

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\\\Distance=\sqrt{(-3-2)^2+(-6-6)^2} \\Distance=\sqrt{(-5)^2+(-12)^2} \\Distance=\sqrt{25+144} \\Distance =\sqrt{169}\\Distance = 13

So, the distance between points A and B is 13

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Find the fourth roots of 16(cos 200° + i sin 200°).
NeTakaya

Answer:

<em>See below.</em>

Step-by-step explanation:

To find roots of an equation, we use this formula:

z^{\frac{1}{n}}=r^{\frac{1}{n}}(cos(\frac{\theta}{n}+\frac{2k\pi}{n} )+\mathfrak{i}(sin(\frac{\theta}{n}+\frac{2k\pi}{n})), where k = 0, 1, 2, 3... (n = root; equal to n - 1; dependent on the amount of roots needed - 0 is included).

In this case, n = 4.

Therefore, we adjust the polar equation we are given and modify it to be solved for the roots.

Part 2: Solving for root #1

To solve for root #1, make k = 0 and substitute all values into the equation. On the second step, convert the measure in degrees to the measure in radians by multiplying the degrees measurement by \frac{\pi}{180} and simplify.

z^{\frac{1}{4}}=16^{\frac{1}{4}}(cos(\frac{200}{4}+\frac{2(0)\pi}{4}))+\mathfrak{i}(sin(\frac{200}{4}+\frac{2(0)\pi}{4}))

z^{\frac{1}{4}}=2(cos(\frac{5\pi}{18}+\frac{\pi}{4}))+\mathfrak{i}(sin(\frac{5\pi}{18}+\frac{\pi}{4}))

z^{\frac{1}{4}} = 2(sin(\frac{5\pi}{18}+\frac{\pi}{4}))+\mathfrak{i}(sin(\frac{5\pi}{18}+\frac{\pi}{4}))

<u>Root #1:</u>

\large\boxed{z^\frac{1}{4}=2(cos(\frac{19\pi}{36}))+\mathfrack{i}(sin(\frac{19\pi}{38}))}

Part 3: Solving for root #2

To solve for root #2, follow the same simplifying steps above but change <em>k</em>  to k = 1.

z^{\frac{1}{4}}=16^{\frac{1}{4}}(cos(\frac{200}{4}+\frac{2(1)\pi}{4}))+\mathfrak{i}(sin(\frac{200}{4}+\frac{2(1)\pi}{4}))

z^{\frac{1}{4}}=2(cos(\frac{5\pi}{18}+\frac{2\pi}{4}))+\mathfrak{i}(sin(\frac{5\pi}{18}+\frac{2\pi}{4}))\\

z^{\frac{1}{4}}=2(cos(\frac{5\pi}{18}+\frac{\pi}{2}))+\mathfrak{i}(sin(\frac{5\pi}{18}+\frac{\pi}{2}))\\

<u>Root #2:</u>

\large\boxed{z^{\frac{1}{4}}=2(cos(\frac{7\pi}{9}))+\mathfrak{i}(sin(\frac{7\pi}{9}))}

Part 4: Solving for root #3

To solve for root #3, follow the same simplifying steps above but change <em>k</em> to k = 2.

z^{\frac{1}{4}}=16^{\frac{1}{4}}(cos(\frac{200}{4}+\frac{2(2)\pi}{4}))+\mathfrak{i}(sin(\frac{200}{4}+\frac{2(2)\pi}{4}))

z^{\frac{1}{4}}=2(cos(\frac{5\pi}{18}+\frac{4\pi}{4}))+\mathfrak{i}(sin(\frac{5\pi}{18}+\frac{4\pi}{4}))\\

z^{\frac{1}{4}}=2(cos(\frac{5\pi}{18}+\pi))+\mathfrak{i}(sin(\frac{5\pi}{18}+\pi))\\

<u>Root #3</u>:

\large\boxed{z^{\frac{1}{4}}=2(cos(\frac{23\pi}{18}))+\mathfrak{i}(sin(\frac{23\pi}{18}))}

Part 4: Solving for root #4

To solve for root #4, follow the same simplifying steps above but change <em>k</em> to k = 3.

z^{\frac{1}{4}}=16^{\frac{1}{4}}(cos(\frac{200}{4}+\frac{2(3)\pi}{4}))+\mathfrak{i}(sin(\frac{200}{4}+\frac{2(3)\pi}{4}))

z^{\frac{1}{4}}=2(cos(\frac{5\pi}{18}+\frac{6\pi}{4}))+\mathfrak{i}(sin(\frac{5\pi}{18}+\frac{6\pi}{4}))\\

z^{\frac{1}{4}}=2(cos(\frac{5\pi}{18}+\frac{3\pi}{2}))+\mathfrak{i}(sin(\frac{5\pi}{18}+\frac{3\pi}{2}))\\

<u>Root #4</u>:

\large\boxed{z^{\frac{1}{4}}=2(cos(\frac{16\pi}{9}))+\mathfrak{i}(sin(\frac{16\pi}{19}))}

The fourth roots of <em>16(cos 200° + i(sin 200°) </em>are listed above.

3 0
3 years ago
G (r) = 25 – 3r<br> g(4) =
tensa zangetsu [6.8K]

Answer:

=25 - 3 × 4

= 25-12= 13

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8 0
3 years ago
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8.42 Three bags of jelly beans contain 26,28 , and 30 beans. In each bag, the percent of the beans that are yellow is 50%, 25%,
olasank [31]

Answer:

Step-by-step explanation:

Figure out the number of yellow beans in each bag:

Bag A: 0.5*26 = 13 beans

Bag B: 0.25*28 = 7 beans

Bag C: 0.2*30 = 6 beans

The total number of beans in the bowl: 26+28+30 = 84

Total number of yellow beans: 13+7+6 = 26

Percentage of yellow beans: 26/84 *100 = 30.9523

Rounded answer: 31%

6 0
2 years ago
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Help with the question above! Pleaseeeeee!
SSSSS [86.1K]
Question 5:
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 C = 2 * pi * r
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 r: radio of the ball
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 22 = 2 * pi * r
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 r = 11 / pi
 The surface area is given by:
 A = 4 * pi * r ^ 2
 Substituting values we have:
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 A = 154 in ^ 2
 Answer:
 
The surface area of the balloon is:
 
A = 154 in ^ 2

 Question 8:
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 V1 = (k ^ 3) * V2
 Substituting values we have:
 729 = (k ^ 3) * 2744
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 Answer:
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The volume of the cylinder is:
 
V = 101.92 * pi
 
option 3
4 0
3 years ago
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A pound of chocolate cost $6. Nicole buys p pounds. Write an equation to represent the total cost of c that Nicole pays.?
leonid [27]

Answer:

C=6p

Step-by-step explanation:

The cost (c) will be by itself since that is the answer you are looking for. 6p is grouped together because for every pound you pay $6. For example if you had 2 pounds of chocolate. You would multiple $6 by 2 and your cost would equal $12

7 0
3 years ago
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