Answer
C41 = 2
This very simple to do.
First locate the entry in A41 in matrix A. That is the entry in the intersection of the fourth row and first column of matrix A. This entry is 7.
Then multiply by the scalar which is 2 to get,
Next we locate the entry in B41 in matrix B also. Which is 4. We multiply by the scalar of -3 to get,
-3 x 4= -12
We now add these two corresponding entries to obtain,
14+-12= 2
Answer: 1:(12^2*10.8)/3=518.4 2: v = 392(3.1415)/3 = 410.5 3: (Πr^2*h) Π*9*15=424
Step-by-step explanation:
Number set:
18, 36, 900
GCF:
9
