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Oksi-84 [34.3K]
3 years ago
14

Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume of carbon tetrachlori

de would be produced by this reaction if 1.1 mL of chlorine were consumed? Be sure your answer has the correct number of significant digits.
Chemistry
1 answer:
mario62 [17]3 years ago
7 0

Answer:

0.55mL of carbon tetrachloride

Explanation:

CH4(g) + 2Cl2(g) -------> CCl4(g) + 2H2(g)

From the balanced reaction equation

44800mL of chlorine produces 22400 ml of carbon tetrachloride

If 1.1mL of chlorine were consumed, volume of carbon tetrachloride= 1.1×22400/44800

=0.55mL of carbon tetrachloride

Note: 1 mole of a gas occupies 22.4L volume or 22400mL

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g100num [7]
It's simple, just follow my steps.

1º - in 1 L we have 0.0100~g of BaCO_3

2º - let's find the number of moles.

\eta=\frac{m}{MM}

\eta=\frac{0.0100}{197.3}

\boxed{\boxed{\eta=5.07\times10^{-5}~mol}}

3º - The concentration will be

C=5.07\times10^{-5}~mol/L

But we have this reaction

BaCO_3\rightleftharpoons Ba^{2+}+CO_3^{2-}

This concentration will be the concentration of Ba^{2+}~~and~~CO_3^{2-}

K_{sp}=\frac{[Ba^{2+}][CO_3^{2-}]}{[BaCO_3]}

considering [BaCO_3]=1~mol/L

K_{sp}=[Ba^{2+}][CO_3^{2-}]

and

[Ba^{2+}]=[CO_3^{2-}]=5.07\times10^{-5}~mol/L

We can replace it

K_{sp}=(5.07\times10^{-5})*(5.07\times10^{-5})

K_{sp}\approx25.70\times10^{-10}

Therefore the K_{sp} is:

\boxed{\boxed{\boxed{K_{sp}\approx2.57\times10^{-11}}}}
4 0
3 years ago
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Which of the following statements about electronic configurations of atoms and mononuclear ions, and atomic orbital quantum numb
ruslelena [56]

Answer:

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b. The valence electronic configuration of strontium is 4d2.  FALSE

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Explanation:

a. The electronic configuration of the hydride anion is 1s² is true since the hydriden anion is the hdrogen atom which has gained an electron and we will add that electron to the 1s¹ configuration of H.

b. The valence electronic configuration of strontium is 4d2 is false since Sr is an element of period 5 , therefore its valece electrons are in in period five and it has 2 electrons because Sr belongs to group 2.

c. For a given value of l the number of possible values of ml is 2l+1 is true since this number gives the magnetic orientation for the sublevel. Thus for s there is only one orientation, then ml = 2 (0 ) +1 . Por p with  l equal to 1 we have three possible orientations : 2(1) + 1 =3. The d and f sublevels have 10 and 14 orientations.

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2 years ago
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Mandarinka [93]
I believe the correct answer to your question is Brittle. Hope I'm correct let me know.
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3 years ago
ASAPPPP EASY!!!!!!!!!!
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Answer:

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Explanation:

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Answer:

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