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vladimir2022 [97]
2 years ago
15

What is the sum of all the oxidation numbers in any compound

Chemistry
1 answer:
andrey2020 [161]2 years ago
4 0

Answer:

The sum of all the oxidation numbers for neutral compound = 0

For charged  species sum of oxidation no. of all the elements is not equal to zero either positive or negative.

Explanation:

In case for neutral compounds sum of total oxidation no. of all elements is equal to zero.

Let us consider for

          K₂Cr₂O₇ (Potassium dichromate) the sum of total oxidation state of elements is equal to zero.

Oxidation state of potassium = +1, For Chromium = +6 & for oxygen = -2        

So total oxidation number

                     2 x (+1) + 2 x (+6) + 7 x (-2)

                 = +14 - 14 = 0.

In case for charged species.

Example for

Ammonium ion (NH₄⁺) total charge = +1

∵ O.N for nitrogen = -3 and for hydrogen = +1

∴ Sum of oxidation numbers = 1 x (-3) + 4 x (+1)

                                             = +1

For Carbonate ion (CO₃²⁻) total charge = -2

Oxidation number for carbon = +4 and for oxygen = -2

(∵Oxygen is more electronegative than carbon)

∴  Sum of oxidation numbers = 1 x (+4) + 3 x (-2) = -2

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The percent error associated with Jason’s measurement is 0.596%.

HOW TO CALCULATE PERCENTAGE ERROR:

  • The percentage error of a measurement can be calculated by following the following process:
  1. Find the difference between the true value and the measured value of a quantity.
  2. Then, divide by the true value and then multiplied by 100

  • The true value of the density of iron is 7.874 g/mL
  • Jason observed value is 7.921 g/mL

Difference = 7.921 g/mL - 7.874 g/mL

Difference = 0.047 g/mL

Percentage error = 0.047/7.874 × 100

Percentage error = 0.596%.

Therefore, the percent error associated with Jason’s measurement is 0.596%.

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