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WINSTONCH [101]
3 years ago
10

Please Help Me!!

Chemistry
1 answer:
Cerrena [4.2K]3 years ago
3 0

Answer:

1. Galvanic oxidation. Example is the corrosion of aluminium wires when in contact with copper wires under wet conditions.

2. Rainwater or Damp/moist air

3. Chromium-plated steel screws or stainless steel screws or galvanized steel screws

Explanation:

1. Galvanic oxidation or corrosion occurs when two different metals with different electrode potentials are brought into contact with each other by means of an electrolyte (usually a aqueous solution), such that a redox reaction occurs leading to one metal with the more negative electrode potential (the anode) becoming oxidized, while the other less negative potential (the cathode) is reduced.

In order for galvanic corrosion to occur, three elements are required.

i. Two metals with different corrosion potentials (anode and cathode)

ii. Direct metal-to-metal electrical contact

iii. A conductive electrolyte solution (e.g. water) must connect the two metals on a regular basis.

For example oxidation (corrosion) of aluminium wires when in contact with copper wire under wet conditions.

2. The most likely electrolyte will be rainwater containing dissoved solutes (if the panel is in an exposed part of the house) or damp/moist air.

3. From the table, the most likely screw will be chromium-plated steel screws or stainless steel (made of iron and nickel) screws or galvanized steel (zinc-plated) screws.

All these possible screw components have a more negative electrode potential than copper. Thus they will serve as the anode in a galvanic oxidation with copper.

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Answer:

43.868 J

Explanation:

Kinetic energy of a body is the amount of energy possessed by a moving body. The SI unit of kinetic energy is the joule (kg⋅m²⋅s⁻²).

According to classical mechanics, kinetic energy = 1/2 m·v²

Where, m= mass in kg and v= velocity in m/s

Given: m = 19.2 lb and v = 7.10 miles/h

Since, 1 lb= 0.453592 kg

∴ m = 19.2 lb = 19.2 × 0.453592 kg = 8.709 kg

Also, 1 mi = 1609.34 m and 1 h = 3600 sec

∴ v = 7.10 mi/h = 7.10 × 1609.34 m ÷ 3600 sec = 3.174 m/sec

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How many photons are produced in a laser pulse of 0.364 J at 477 nm?
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Answer:

1.00 × 10¹⁸

Explanation:

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The formula for the energy of a photon is

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<em>h</em> = 6.626 × 10⁻³⁴ J·s; <em>c</em> = 2.998 × 10⁸ m·s⁻¹

λ = 477 nm = 477 × 10⁻⁹ m                              Insert the values

<em>E</em> = (6.626 × 10⁻³⁴ × 2.998× 10⁸)/(477 × 10⁻⁹)

<em>E</em> = 4.165× 10⁻¹⁹ J

2. Calculate the <em>number of photons</em>

Divide the total energy by the energy of one photon.

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7 0
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