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3 years ago

Is it possible for two different materials to have different solubilities

1 answer:

4 0

Yes it is! Depending on the chemical make up of the material, it can have different solubility levels. For example, lipids have a low solubility in Water because of the non polar make up :)

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List two things you know about nonrenewable energy

Contact [7]

It is natural and u can't by it

6 0

4 years ago

Read 2 more answers

Ammonium (NH4+), carbonate (CO32−), and phosphate (PO43−) are all examples of: (a) multivalent metals (b) polyatomic ions (c) co

PtichkaEL [24]

Answer:

Option b) polyatomic ions

Explanation:

Polyatomic ions are ions consisting of two or more atoms.

From the question given above, we can see that each ions consist of more than one atom as shown below:

Ions >>>>>> Number of atom present

NH4+ >>>>> 2

CO32− >>>> 2

PO43− >>>> 2

Thus, we can say that the above ions are polyatomic ions.

5 0

3 years ago

How many pili are in a bacterial cell

Snowcat [4.5K]

Answer: Bacterial species where observed Typical number on cell Distribution on cell surface

Escherichia coli (common pili or Type 1 fimbriae) 100-200 uniform

Neisseria gonorrhoeae 100-200 uniform

Streptococcus pyogenes (fimbriae plus the M-protein) ? uniform

Pseudomonas aeruginosa 10-20 polar

Explanation:

Pili are structures that extend from the surface of some bacterial cells.

These are hollow, non-helical, filamentous appendages.

Hope it helps you

7 0

3 years ago

222 g of MTBE (CO(CH3)4) are added to gasoline, resulting in a total volume of 2 L of reformulated gas (RFG). Assume that the de

Eva8 [605]

Answer:

Explanation:

From the information given:

(a)

$Concentration \ in \ mg/L = \dfrac{Mass \ of \ MTBE \ in \ mg}{Total \ volume (in \ L)}$

$Concentration \ in \ mg/L = \dfrac{222 \times 10^3 \ mg}{22}$

$Concentration \ in \ mg/L = 111 \times 10^3 \ mg/L$

(b)

$number \ of \ mole s= \dfrac{mass}{molar \ mass } \\ \\ number \ of \ mole s=\dfrac{222 \ g}{88.15 \ g/mol} \\ \\ \mathbf{= 2.518 mol}$

(c)

$w/w \ percentage = \dfrac{mass \ of \ MTBE }{mass \ of \ solution (RFG)}\times 100\%$

$where; \\ \\ mass \ of \ (RFG) = 2L \times 0.70 g/mL \\ \\ mass \ of \ (RFG) = 2000 ml \times 0.70 g/mL \\ \\ mass \ of \ (RFG) = 1400 g$

∴

$w/w \ percentage = \dfrac{222 \ g}{1400 \ g}\times 100\% = \mathbf{15.8\%}$

(d)

$Volume of MTBE =\dfrac{mass \ of \ MTBE}{density \ of \ MTBE}$

$Volume \ of \ MTBE = 300 \ mL\\$

∴

$v/v\% = \dfrac{volume \ of \ MTBE}{volume \ of \ RFG} \\ \\ v/v\% =\dfrac{300 \ mL}{2000 \ mL}\times 100\% \\ \\ \mathbf{v/v\% = 15.00\%}$

(e)

$From \the \ given \ information; \\ \\ 2.5184 \ moles\ of \ MTBE contain \ 2.5184 \ mole of oxygen$

∴

$mass of oxygen MTBE = 2.5284 mol \times 16\ g/mol \\ \\ mass of oxygen MTBE = 40.3 9 \ g\\ \\ mass\ of \ RFG = 1400 g$

∴

$\% w/w = \dfrac{mass \ of \ oxygen}{mass \ of RFG }=\dfrac{40.22 \ g}{1400 \ g} \times 100\%$

$\% w/w == 2.88\%$

3 0

3 years ago

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The different substance in a mixture

SashulF [63]

Mixture is physically combined and substance is chemically combined and can only be changed in identity and properties by chemical methods

5 0

3 years ago